Can you delete a pointer without newing it up? (modified version)

[asimorio]

All,
Well, now i modify a bit my code:
Will it make sense?

void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}


regards,
Vynce

 

[Sharad Kala]

| All,
| Well, now i modify a bit my code:
| Will it make sense?

It will only be legal if the memory pointed to by a has been obtained by a
call to new operator. Also if the pointer is NULL, then delete has no
effects.

Sharad

| void A::Foo(void* a)
| {
| char* buffer = (char*) a;
| delete buffer;
| return;
| }

 

[Jim Langston]

All,
Well, now i modify a bit my code:
Will it make sense?

void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}

It depends if a was allocated with new or not. If a was allocated with new,
it is legal. If it was not allocated with new, it is undefined and will
most likely cause a memory fault.

 

[Tomás]

asimorio posted:

All,
Well, now i modify a bit my code:
Will it make sense?

void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}

There are two sole conditions under which that would work:

int main()
{
A::Foo( new char );

A::Foo( 0 );
}


-Tomás

 

[Default User]

All,
Well, now i modify a bit my code:
Will it make sense?

void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}

What are actually trying to do? What problem are you solving? What you
propose is rarely a good idea.




Brian