casting _to_ a class/struct

[.rhavin grobert]

Hi there;-)

I have the following struct:

struct foo {
union {
unsigned __int64 ui64;
char[8] c;
};
};

what i now want to make possible is...

foo a;
foo b;
int c;
foo d;
a = "abcdefg";
b = 12;
d = (foo) c;

so i think i need to globally overload the cast operator, isn't it?

i know how to overload the cast-operator to convert from my struct to
$type, but how do i do it the other way 'round?

thanx for your help,

-.rhavin

 

[Andre Kostur]

Hi there;-)

I have the following struct:

struct foo {
union {
unsigned __int64 ui64;
char[8] c;
};
};

what i now want to make possible is...

foo a;
foo b;
int c;
foo d;
a = "abcdefg";
b = 12;
d = (foo) c;

so i think i need to globally overload the cast operator, isn't it?

Why not assignment operators?

foo & foo:perator=(__int64 newvalue)
{
ui64 = newvalue;
}

foo & foo:perator=(const char * cp)
{
strncpy(c, cp, sizeof(c));
}

i know how to overload the cast-operator to convert from my struct to
$type, but how do i do it the other way 'round?

That would require you to overload operators on int.... can't be done.

 

[Victor Bazarov]

[..]
i know how to overload the cast-operator to convert from my struct to
$type, but how do i do it the other way 'round?

I think you're talking about a parameterised constructor here.

V

 

[Sylvester Hesp]

Why not assignment operators?

Because that won't solve the '(foo)c' piece of code . Constructors are the
way to go (best in combination with assignment operators, but the latter
won't be needed to make it all work).

- Sylvester