Comparing variable to multiple values

[Greg Lazarev]

I'm wondering if there's a better way to do this in ruby:

if a == "word1" || a == "word2" or || a == "word3"
puts "good"
end

 

[Alex Fenton]

I'm wondering if there's a better way to do this in ruby:

if a == "word1" || a == "word2" or || a == "word3"
puts "good"
end

if ["word1", "word2", "word3"].include?(a)
puts 'good'
end

OR

case a
when "word1", "word2", "word3"
puts 'good'
end

hth
a

 

[Victor H. Goff III]

[Note: parts of this message were removed to make it a legal post.]

strings_array = ['word1', 'word2', 'word3']
a = 'word1'
puts "good" if strings_array.include?(a)

 

[Brian Adkins]

I'm wondering if there's a better way to do this in ruby:

if a == "word1" || a == "word2" or || a == "word3"
puts "good"
end

I realize that you probably want a more general solution (which others
have already provided); however, if 'a' *does* follow a pattern:

puts 'good' if a =~ /word[1-3]/

or

puts 'good' if a =~ /word\d+/

 

[Peña, Botp]

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IHcgbW9yZSBjYXNlcywgYW5kICBiZWF1dGlmeSBhcyBpIGdvLi4uDQo=

 

[Robert Klemme]

I'm wondering if there's a better way to do this in ruby:

if a == "word1" || a == "word2" or || a == "word3"
puts "good"
end

I realize that you probably want a more general solution (which others
have already provided); however, if 'a' *does* follow a pattern:

puts 'good' if a =~ /word[1-3]/

or

puts 'good' if a =~ /word\d+/

You forgot the anchors. Your regexp will also match "fooword1bar" which
was not intended by OP. Also, IIRC it is more efficient to switch
sides, i.e.

puts 'good' if /\Aword[1-3]\z/ =~ a

For _large_ sets of words which do not follow a simple pattern a Set may
be more efficient

TEST = %w{word1 word2 word3 plus many more words}.to_set.freeze

puts 'good' if TEST.include? a

Kind regards

robert

 

[Siep Korteling]

puts 'good' if a =~ /word[1-3]/

or

puts 'good' if a =~ /word\d+/

You forgot the anchors. Your regexp will also match "fooword1bar" which
was not intended by OP. (...)

Kind regards

robert

Is this a bug?

("word1".."word3").each{|w| puts w}
=> word1
=> word2
=> word3
puts "good" if ("word1".."word3").include?("word1bar")
=> good

If so, what am I supposed to do?


Siep

 

[Peña, Botp]

RnJvbTogU2llcCBLb3J0ZWxpbmcgW21haWx0bzpzLmtvcnRlbGluZ0BnbWFpbC5jb21dIA0KIyBw
dXRzICJnb29kIiBpZiAoIndvcmQxIi4uIndvcmQzIikuaW5jbHVkZT8oIndvcmQxYmFyIikNCiMg
PT4gZ29vZA0KIyBJZiBzbywgd2hhdCBhbSBJIHN1cHBvc2VkIHRvIGRvPw0KDQpydWJ5IHJhbmdl
IGlzIGp1c3QgYmVpbmcgZnJpZW5kbHksIHNvIGRvIG5vdCByZWx5IHRvbyBtdWNoIDspDQp0byBi
ZSBleHBsaWNpdCwgY29udmVydCBpdCB0byBhcnJheSB0aGVuDQoNCj4gcHV0cyAiZ29vZCIgaWYg
KCJ3b3JkMSIuLiJ3b3JkMyIpLnRvX2EuaW5jbHVkZT8oIndvcmQxYmFyIikNCj0+IG5pbA0K

 

[Brian Adkins]

puts 'good' if a =~ /word[1-3]/

or

puts 'good' if a =~ /word\d+/

You forgot the anchors. Your regexp will also match "fooword1bar"
which was not intended by OP. Also, IIRC it is more efficient to
switch sides, i.e.

Interesting - I wouldn't think there would be a difference, but I just
benchmarked it and it appears that putting the pattern on the left
gives a 1.2% speed boost.