converting base class instance to derived class instance

S

Sridhar R

Consider the code below,

class Base(object):
pass

class Derived(object):

def __new__(cls, *args, **kwds):
# some_factory returns an instance of Base
# and I have to derive from this instance!
inst = some_factory() # this returns instance of Base
return inst # Oops! this isn't an instance of Derived

def __init__(self):
# This won't be called as __new__ returns Base's instance
pass

The constrait is there is some factory function that creates an
instance of Base class. So I _can't_ call "Base.__init__(self)" in
Derived.__init__ func, as their will be _two_ instances (one created
by Derived.__init__ and other created by the factory function)

Simply I want to get a derived class object, but instead of allowing
_automatic_ creation of Base instance, I want to use _existing_ Base's
instance, then use this as a Derived's instance.

Will metaclass solve this problem?
 
P

Peter Otten

Sridhar said:
Consider the code below,

class Base(object):
pass

class Derived(object):

I suppose that should be

class Derived(Base):
def __new__(cls, *args, **kwds):
# some_factory returns an instance of Base
# and I have to derive from this instance!
inst = some_factory() # this returns instance of Base

# using brute force:
inst.__class__ = Derived

No guarantees, but the above seems to work.
return inst # Oops! this isn't an instance of Derived

def __init__(self):
# This won't be called as __new__ returns Base's instance
pass

The constrait is there is some factory function that creates an
instance of Base class. So I _can't_ call "Base.__init__(self)" in
Derived.__init__ func, as their will be _two_ instances (one created
by Derived.__init__ and other created by the factory function)

As some_factory() returns an already initialized instance of Base, there
should be no need to call it again from inside Derived.__init__()
Simply I want to get a derived class object, but instead of allowing
_automatic_ creation of Base instance, I want to use _existing_ Base's
instance, then use this as a Derived's instance.

Will metaclass solve this problem?

I think metaclasses will solve only metaproblems...

Skeptically yours,
Peter
 
J

John Roth

Sridhar R said:
Consider the code below,

class Base(object):
pass

class Derived(object):

def __new__(cls, *args, **kwds):
# some_factory returns an instance of Base
# and I have to derive from this instance!
inst = some_factory() # this returns instance of Base
return inst # Oops! this isn't an instance of Derived

def __init__(self):
# This won't be called as __new__ returns Base's instance
pass

__new__ can return an instance of any class it pleases.
It's not restricted to returning an instance of the class it
happens to be in, nor is it restricted to returning a newly
created instance, for that matter. It can do the entire
construction job without using the __init__ method.

However, I don't think that's the best solution. If
your factory is going to return instances of several
different classes, I think it's best that it be an explicit
factory method or function, not something that magically
happens in a class constructor. I'd rather not have to
deal with programs where class constructors pass me
instances of classes other than the one I'm calling.

If you want to do a little bit of deep magic, a factory
function can create an instance by calling object(),
plug in whatever attributes it wants and then change the
__class__ attribute to whatever class it wants before
it returns the newly minted instance. It doesn't have to
go near anything that resembles a constructor (other than
calling object() to get a new instance, of course.)
The constraint is there is some factory function that creates an
instance of Base class. So I _can't_ call "Base.__init__(self)" in
Derived.__init__ func, as their will be _two_ instances (one created
by Derived.__init__ and other created by the factory function)

Simply I want to get a derived class object, but instead of allowing
_automatic_ creation of Base instance, I want to use _existing_ Base's
instance, then use this as a Derived's instance.

Will metaclass solve this problem?

Wrong tool. Metaclasses are used to set up classes, not to
set up instances.

John Roth
 
M

Michele Simionato

Consider the code below,

class Base(object):
pass

class Derived(object):

def __new__(cls, *args, **kwds):
# some_factory returns an instance of Base
# and I have to derive from this instance!
inst = some_factory() # this returns instance of Base
return inst # Oops! this isn't an instance of Derived

def __init__(self):
# This won't be called as __new__ returns Base's instance
pass

The constrait is there is some factory function that creates an
instance of Base class. So I _can't_ call "Base.__init__(self)" in
Derived.__init__ func, as their will be _two_ instances (one created
by Derived.__init__ and other created by the factory function)

Simply I want to get a derived class object, but instead of allowing
_automatic_ creation of Base instance, I want to use _existing_ Base's
instance, then use this as a Derived's instance.

Will metaclass solve this problem?

I don't really understand what you want to do (i.e. do you want
Derived.__init__ to be called or not?). Moreover, as others pointed
out, it is cleaner to use a class factory than to pervert __new__.
If you really want to use a metaclass, you could override the
__call__ method of the metaclass, in such a way to interfer with the
class instantiation. For instance, this is the code to make a singleton
class (which is a FAQ ;)

class Singleton(type):
"Instances of this metaclass are singletons"
def __init__(cls,name,bases,dic):
super(Singleton,cls).__init__(name,bases,dic)
cls.instance=None
def __call__(cls,*args,**kw):
if cls.instance is None:
cls.instance=super(Singleton,cls).__call__(*args,**kw)
return cls.instance

class C:
__metaclass__=Singleton

This is not what you want but you can play with __call__ and get
the behavior you want. Still, why don't just use a simple factory?

Michele Simionato
 
?

=?iso-8859-1?Q?Fran=E7ois?= Pinard

[John Roth]
If you want to do a little bit of deep magic, a factory function can
create an instance by calling object(), plug in whatever attributes
it wants and then change the __class__ attribute to whatever class it
wants before it returns the newly minted instance. It doesn't have
to go near anything that resembles a constructor (other than calling
object() to get a new instance, of course.)

Hello, John, and gang! :)

How one does that? I'm merely curious. Using Python 2.3.3, the result
of `object()' does not have a `__dict__', and seemingly may not be given
a `__dict__' either. See:


Python 2.3.3 (#1, Jan 24 2004, 09:01:30)
[GCC 3.3 20030226 (prerelease) (SuSE Linux)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
from __future__ import divisionTraceback (most recent call last):
Traceback (most recent call last):
Traceback (most recent call last):


By the way, what is a "heap type"?
 
J

John Roth

[John Roth]
If you want to do a little bit of deep magic, a factory function can
create an instance by calling object(), plug in whatever attributes
it wants and then change the __class__ attribute to whatever class it
wants before it returns the newly minted instance. It doesn't have
to go near anything that resembles a constructor (other than calling
object() to get a new instance, of course.)

Hello, John, and gang! :)

How one does that? I'm merely curious. Using Python 2.3.3, the result
of `object()' does not have a `__dict__', and seemingly may not be given
a `__dict__' either. See:

[John's answer]
My goof. The correct call is:

object.__new__(klas)

where klas is the class object you want
the instance constructed for.


John Roth
 
G

Gerrit

Fran�ois Pinard said:
By the way, what is a "heap type"?

I don't know, but:

http://foldoc.doc.ic.ac.uk/foldoc/foldoc.cgi?query=heap&action=Search

heap

1. <programming> An area of memory used for dynamic memory allocation
where blocks of memory are allocated and freed in an arbitrary order and
the pattern of allocation and size of blocks is not known until run
time. Typically, a program has one heap which it may use for several
different purposes.

Heap is required by languages in which functions can return arbitrary
data structures or functions with free variables (see closure). In C
functions malloc and free provide access to the heap.

Contrast stack. See also dangling pointer.

2. <programming> A data structure with its elements partially ordered
(sorted) such that finding either the minimum or the maximum (but not
both) of the elements is computationally inexpensive (independent of the
number of elements), while both adding a new item and finding each
subsequent smallest/largest element can be done in O(log n) time, where
n is the number of elements.

Formally, a heap is a binary tree with a key in each node, such that all
the leaves of the tree are on two adjacent levels; all leaves on the
lowest level occur to the left and all levels, except possibly the
lowest, are filled; and the key in the root is at least as large as the
keys in its children (if any), and the left and right subtrees (if they
exist) are again heaps.

Note that the last condition assumes that the goal is finding the
minimum quickly.

Heaps are often implemented as one-dimensional arrays. Still assuming
that the goal is finding the minimum quickly the invariant is

heap <= heap[2*i] and heap <= heap[2*i+1] for all i,


where heap denotes the i-th element, heap[1] being the first.
Heaps can be used to implement priority queues or in sort algorithms.


And:

http://www.python.org/dev/doc/devel/lib/module-heapq.html
Heaps are arrays for which heap[k] <= heap[2*k+1] and heap[k] <=
heap[2*k+2] for all k, counting elements from zero. For the sake of
comparison, non-existing elements are considered to be infinite. The
interesting property of a heap is that heap[0] is always its smallest
element.

Gerrit.
 
?

=?iso-8859-1?Q?Fran=E7ois?= Pinard

[John Roth]
If you want to do a little bit of deep magic, a factory function can
create an instance by calling object(), [...] My goof. The correct
call is: object.__new__(klas) [...]

OK, thanks. `object.__new__' is what I was using already. It was
looking kosher to me because of the explanations in `descrintro'. Maybe
I was seduced and tempted by the announced bit of deep magic, and was
trying to rediscover the secret. My little Harry Potter side! :)
 
?

=?iso-8859-1?Q?Fran=E7ois?= Pinard

[Gerrit]
[François Pinard]
By the way, what is a "heap type"?
http://foldoc.doc.ic.ac.uk heap [...] 1. An area of memory [...]
2. A data structure [...]

Wow, Gerrit, I appreciate your effort in providing this comprehensive
answer (and am saving the reference to `foldoc', which looks useful).
My question was likely ambiguous, sorry. Reading "heap type" in an
article written in the context of Python new-style classes, I wondered
if "heap type" did not refer to some classification of Python types
which I did not know, but should know.

If you follow the `Theory' link from the page above, you might see that
I wrote this explanation. The editor was kind above to push my name in
there :). Not really that I expected it, it even surprised me. On the
other hand, it officialises a tiny bit the fact that I much like Python!
 
J

John Roth

Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: __class__ assignment: only for heap types


By the way, what is a "heap type"?


I think they're refering to objects that are allocated
on the heap. I'm not sure what attempting to
instantiate object would do, but I suspect the result
would be a built-in that can't be modified.

John Roth
 
?

=?iso-8859-1?Q?Fran=E7ois?= Pinard

[John Roth]
[François Pinard]
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: __class__ assignment: only for heap types
By the way, what is a "heap type"?
I think they're refering to objects that are allocated on the
heap. I'm not sure what attempting to instantiate object would do, but
I suspect the result would be a built-in that can't be modified.

Someone suggested, on this list, that `object()' could be used for
cheaply producing an object which is guaranteed unique, when there is no
need for that object to have any other property.

If you do:

a = object()
b = object()
c = object()
...

you will observe that they are all different, none of `a', `b', `c'
compare with `is' to another. I do not see how the result could be
built-in or pre-allocated.

I could understand that some immutable objects, like 0, "z" or () could
be allocated statically. But for `object()', I do not see.
 
J

John Roth

[John Roth]
[François Pinard]
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: __class__ assignment: only for heap types
By the way, what is a "heap type"?
I think they're refering to objects that are allocated on the
heap. I'm not sure what attempting to instantiate object would do, but
I suspect the result would be a built-in that can't be modified.

Someone suggested, on this list, that `object()' could be used for
cheaply producing an object which is guaranteed unique, when there is no
need for that object to have any other property.

If you do:

a = object()
b = object()
c = object()
...

you will observe that they are all different, none of `a', `b', `c'
compare with `is' to another. I do not see how the result could be
built-in or pre-allocated.

I could understand that some immutable objects, like 0, "z" or () could
be allocated statically. But for `object()', I do not see.

[John Roth]
But I believe that object itself is a built-in type, and the error
message in question specified "heap TYPE".

John Roth
 
?

=?iso-8859-1?Q?Fran=E7ois?= Pinard

?

=?iso-8859-1?Q?Fran=E7ois?= Pinard

[John Roth]
But I believe that object itself is a built-in type, and the error
message in question specified "heap TYPE".

I understand what you say, and it sounds logical. Thanks!
 

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