Decimal.Round() function return result false

[Hoang Duc Chau]

Hi Guy,
Dim dTestA As Decimal = Decimal.Round(6.75, 1)
dTestA return 6.8 (right)
Dim dTestB As Decimal = Decimal.Round(6.65, 1)
dTestB return 6.6 (false) while i expected the result is 6.7
Any idea on how to solve this?

Thanks
Hoang Duc Chau

 

[Damien]

Hi Guy,
Dim dTestA As Decimal = Decimal.Round(6.75, 1)
dTestA return 6.8 (right)
Dim dTestB As Decimal = Decimal.Round(6.65, 1)
dTestB return 6.6 (false) while i expected the result is 6.7
Any idea on how to solve this?

Thanks
Hoang Duc Chau

By default, it uses "Bankers Rounding". There are ways to change this
behaviour, and we had a discussion either in here or in
microsoft.public.dotnet.framework recently, so google on that.

Damien

 

[levitymn]

Decimal.Round() seems to have changed in .Net 2.0. The second parameter is no longer a specification of decimal places but an enumeration specifying how it will round to an integer. The MSDN documentation (http://msdn2.microsoft.com/en-us/library/system.decimal_members.aspx) on the function states that the function is new in .net 2.0. So you should use System.Math.Round() to round your decimal values.

 

[pk.noushad]

This issue is there in C# also. Resolution

This issue is there in C# also.

I used following solution to resolve. May this help somebody.

decimal dVaue = 1777.325M;
decimal dRounded = Decimal.Parse(dVaue.ToString("0.00"));

-- Noushad