does a program work in all cases?

[Default User]

though, >> that it doesn't actually forbid NULL expanding to
((void*)0) - a >> compiler could special-case this to not be an error
when assigned to >> other pointers.

Right. Like I said, it misses the point of having void * at all.

No, it doesn't. It provides a way to pass any pointer INTO a function.
So at best you could say it misses half the point of a void*.

In actual practice, void* isn't used much in C++. Generally you use
function overloading or pointers to a family of types, relying on
runtime polymorphism.




Brian

 

[pete]

No, it doesn't. It provides a way to pass any pointer INTO a function.

You could do that much with a pointer to char,
before there was such a keyword as "void", in the 1970's, man!

 

[Default User]

You could do that much with a pointer to char,
before there was such a keyword as "void", in the 1970's, man!

Not without casting every usage. That's what Random832 was complaining
about.



Brian