effect of b = a++ + a++

[Ravi]

what is the effect of fllowing code n values of a and b
b = 0;
a = 1;
b = a++ + a++;

 

[Vimal Aravindashan]

what is the effect of fllowing code n values of a and b
b = 0;
a = 1;
b = a++ + a++;

Please refer to section 3 (Expressions) of the FAQ. Here is a link to
the same: http://www.c-faq.com/expr/index.html.

Regards,
Vi

 

[friendfish]

what is the effect of fllowing code n values of a and b
b = 0;
a = 1;
b = a++ + a++;

That is "(b= (a++)+(a++))", after that b=2 and a=3;

 

[Martien Verbruggen]

That is "(b= (a++)+(a++))", after that b=2 and a=3;

Neither the C standard or the FAQ agree with you.

Maybe on your particular compiler it works like that, but you have no
guarantee that it will work like that anywhere else.

See another post in this same thread for a reference to the C FAQ that
explains why you should not do this.

Martien

 

[Joachim Schmitz]

That is "(b= (a++)+(a++))", after that b=2 and a=3;

Not neccessarily. Read the FAQs as mentioned by a previous poster.

Bye, Jojo

 

[Randy Howard]

Not neccessarily. Read the FAQs as mentioned by a previous poster.

I get this from the compiler:
b.c: In function Œmain¹:
ub.c:10: warning: operation on Œa¹ may be undefined

'May' being an interesting spin on things.

 

[Kaz Kylheku]

what is the effect of fllowing code n values of a and b
b = 0;
a = 1;
b = a++ + a++;

The effect is that it stupefies the reader to the point that he's
unable to read the FAQ or operate the Google search engine.

 

[Martin Ambuhl]

That is "(b= (a++)+(a++))", after that b=2 and a=3;

No, after that the value of b is undefined. Please learn about sequence
points.

This is yet another example of a tiresome error adequately discussed in
the FAQ. Unfortunately, the same people that "know" what this
ill-formed code means are the same ones who won't bother reading the FAQ
or following the newsgroup before posting.

 

[Kaz Kylheku]

That is "(b= (a++)+(a++))", after that b=2 and a=3;

Please don't answer questions in the newsgroup if you haven't read and
understood the FAQ.

You look like an ignorant ass who doesn't know anything, and can't be
bothered to do as little as three minutes of basic research before
submitting an article.

 

[CBFalconer]

That is "(b= (a++)+(a++))", after that b=2 and a=3;

No. The only effect is undefined behaviour. Anything at all can
happen. You could find yourself 6 mos. pregnant (although the
likelihood is probably low).

 

[MisterE]

what is the effect of fllowing code n values of a and b
b = 0;
a = 1;
b = a++ + a++;

just do b=a+a; a+=2; and stop being a **** head

 

[santosh]

news:5419df4d-848a-441c-b02f-0f16b7dfd974@i72g2000hsd.googlegroups.com...

just do b=a+a; a+=2; and stop being a **** head

Neither will do what the OP's code does, simply because the OP code is
undefined.