enlarge Variablenames

[Ugur Boss]

my Problem ist following:

$nr1 = 1;
$nr2 = 2;

$name.$nr = "Hello";

I have tried following way:

${"name".$nr} = "Hello";

But it doesn´t work. Is there another way to solve my problem?

greetings

 

[Paul Lalli]

my Problem ist following:

$nr1 = 1;
$nr2 = 2;

$name.$nr = "Hello";

I have tried following way:

${"name".$nr} = "Hello";

But it doesn´t work. Is there another way to solve my problem?

You haven't described what your problem is. What exactly are you trying
to achieve?

Note that I'm going to make a *guess* that you are trying to use a
variable as a variable name. This is A Bad Idea. For more information on
why this is A Bad Idea, and how to do what you *should* do instead, please
read the FAQ entry "How can I use a variable as a variable name":

perldoc -q 'variable name'

Paul Lalli

 

[Jürgen Exner]

my Problem ist following:

$nr1 = 1;
$nr2 = 2;

$name.$nr = "Hello";

This is not Perl. Are you thinking about a "record" like in Modula or
Pascal?
The closest Perl data structure would be a hash:
$name{$nr} = "Hello";

jue

 

[Ugur Boss]

I try to enlarge the variablename of my scalar $name so that i have
later a variable named $name666 or $name999 with the value "Hello".

 

[Paul Lalli]

[please post your replies *below* the text you are replying to]

I try to enlarge the variablename of my scalar $name so that i have
later a variable named $name666 or $name999 with the value "Hello".

Yes. This is what I said. You are trying to use a variable (in this case
$nr1 or $nr2) as part of a variable name. This is not a good idea.
Please read the FAQ I mentioned in my previous reply. If you do not
understand something in that FAQ, let us know what you don't understand.

Paul Lalli

 

[Jürgen Exner]

[Please do not top-post]
[Please trim the quoted text to a reasonble amout that is needed for
context]

I try to enlarge the variablename of my scalar $name so that i have
later a variable named $name666 or $name999 with the value "Hello".

This is A Bad Idea.
Please see 'perldoc -q "variable name"' why and what to do instead.

jue

 

[Andrew DeFaria]

[Please do not top-post]
[Please trim the quoted text to a reasonble amout that is needed for
context]

Also, aren't these top posts? ;-)

Not I whole heartedly agree with Jügen, trim, trim, trim! Way too much
excess is quoted.

 

[gnari]

[Please do not top-post]
[Please trim the quoted text to a reasonble amout that is needed for
context]

Also, aren't these top posts? ;-)

not really. these were general comments that did not depend on any
quoted text. Jürgen could have stopped there but decided to
also reply to the top-poster, and did that properly quoted, of
course

gnari

 

[Joe Smith]

my Problem ist following:

$nr1 = 1;
$nr2 = 2;

$name.$nr = "Hello";

my %name; # Use a hash
$name{666} = "Number of the beast";
$name{foo} = "bar";
$name{$nr1} = "one";
$name{$nr2} = "two";