getopt: how to carry more than one argument?

[zwylinux]

while ((c = getopt (argc, argv, ":a:")) != -1) {
switch (c)
case 'a':
v_a = 1;
a_list = optarg;
break;
............
............
}

printf ("%s\n", a_list);

the output is:
$./a.out -a aa bb
aa

so bb is missing, but i suppose aa and bb are both arguments of option
-a.
How can I do that?

 

[Jack Klein]

while ((c = getopt (argc, argv, ":a:")) != -1) {
switch (c)
case 'a':
v_a = 1;
a_list = optarg;
break;
............
............
}

printf ("%s\n", a_list);

the output is:
$./a.out -a aa bb
aa

so bb is missing, but i suppose aa and bb are both arguments of option
-a.
How can I do that?

There is no getopt() function in the C standard, so its definition and
use if not topical here. I would suggest asking in a group that
supports your particular compiler, or perhaps
or if
either of these is your platform.

--
Jack Klein
Home: http://JK-Technology.Com
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