Getting a module's code object

[Arnaud Delobelle]

Hi all,

In Python 3, a function f's code object can be accessed via f.__code__.

I'm interested in getting a module's code object, i.e. the code that
is executed when the module is run. I don't think it's accessible via
the module object itself (although I would be glad if somebody proved
me wrong . In the marshal module docs [1] it is mentioned that:

"""
The marshal module exists mainly to support reading and writing the
“pseudo-compiled†code for Python modules of .pyc files.
"""

So it seems that the module's code object is marshalled into the .pyc
file - so there may be a way to unmarshal it - but I can't easily find
information about how to do this.

Is this a good lead, or is there another way to obtained a module's code object?

Thanks

 

[Peter Otten]

In Python 3, a function f's code object can be accessed via f.__code__.

I'm interested in getting a module's code object, i.e. the code that
is executed when the module is run. I don't think it's accessible via
the module object itself (although I would be glad if somebody proved
me wrong . In the marshal module docs [1] it is mentioned that:

"""
The marshal module exists mainly to support reading and writing the
“pseudo-compiled†code for Python modules of .pyc files.
"""

So it seems that the module's code object is marshalled into the .pyc
file - so there may be a way to unmarshal it - but I can't easily find
information about how to do this.

Is this a good lead, or is there another way to obtained a module's code
object?

Taken from pkgutil.py:

def read_code(stream):
# This helper is needed in order for the PEP 302 emulation to
# correctly handle compiled files
import marshal

magic = stream.read(4)
if magic != imp.get_magic():
return None

stream.read(4) # Skip timestamp
return marshal.load(stream)

Alternatively you can compile the source yourself:

module = compile(source, filename, "exec")

 

[Arnaud Delobelle]

In Python 3, a function f's code object can be accessed via f.__code__.

I'm interested in getting a module's code object,

[...]

Taken from pkgutil.py:

def read_code(stream):
   # This helper is needed in order for the PEP 302 emulation to
   # correctly handle compiled files
   import marshal

   magic = stream.read(4)
   if magic != imp.get_magic():
       return None

   stream.read(4) # Skip timestamp
   return marshal.load(stream)

This works fine, thanks a lot!

Alternatively you can compile the source yourself:

module = compile(source, filename, "exec")

I don't necessarily have access to the source file.