How do I search a extract only a few elements in a huge JS array

[mdh_2972]

I have an array of over 1000 links in a .JS file. I do not want to put
the whole thing on my page because it would take to long to render the
page. So how can I randomly pick 1 element from the array and then have
the browser just place the 1 element only on my webpage.

Also I also would like to know how to search for text in the array
element and place it on my webpage.

The first example is my main question.

 

[Jonas Geiregat]

I have an array of over 1000 links in a .JS file. I do not want to put
the whole thing on my page because it would take to long to render the
page. So how can I randomly pick 1 element from the array and then have
the browser just place the 1 element only on my webpage.

Also I also would like to know how to search for text in the array
element and place it on my webpage.

The first example is my main question.

search for a random generator and use the generated number as the array
for your second question just make a loop:
for(i=0 i< array.length; i++)
if("string" == array)
//found !!

good luck!

 

[RobG]

I have an array of over 1000 links in a .JS file. I do not want to put
the whole thing on my page because it would take to long to render the
page. So how can I randomly pick 1 element from the array and then have
the browser just place the 1 element only on my webpage.

function returnRandomElement(linkArray){
return linkArray[Math.random()*linkArray.length|0];
}

Where 'linkArray' is something like:

var linkArray = [
'http://www.google.com',
'http://www.yahoo.com',
'http://www.jibbering.com/faq'
];

Also I also would like to know how to search for text in the array
element and place it on my webpage.

Using the above array as an example, the following function will return
the first link that has text matching 'text':

function returnMatchLink(linkArray, text){
var i = linkArray.length;
var re = new RegExp(text);
while (i--){
if (re.test(linkArray)){
return linkArray;
}
}
return 'not found...';
}

<button onclick="
document.getElementById('xx').innerHTML =
returnMatchLink(linkArray, 'yahoo');
">get 'google'</button>
<div id="xx"></div>


Using a substring method rather than a regular expression may be
faster.

 

[Dr John Stockton]

JRS: In article <[email protected]>, dated Wed,
2 Aug 2006 23:41:52 remote, seen in Jonas

search for a random generator

Bad advice. Searching may find a bad generator. WHENEVER the newsgroup
FAQ addresses a topic, MAKE SURE that your response is at least as good
- and, if it's not significantly better, answer by citing the FAQ.

FAQ 4.22; 4.15.

and use the generated number as the array

^ index

for your second question just make a loop:
for(i=0 i< array.length; i++) ^ ;
if("string" == array)
//found !!

But he wants to search for text in the array element, not necessarily
for a whole element. For that, the .indexOf and .search methods of
String, or methods of RegExp, can be used; they are described in the
usual references. To write the text, FAQ 4.15.

Read the newsgroup FAQ.