How do I write a reg expression to search for NOT a substring?

[Larry Woods]

I want a regular expression that will return TRUE if there is NOT a
substring in the string. Example: Return true if the substring "image" is
NOT in the string.

TIA,

Larry Woods

 

[Lasse Reichstein Nielsen]

I want a regular expression that will return TRUE if there is NOT a
substring in the string. Example: Return true if the substring "image" is
NOT in the string.

That is hard.

It is much easier to return true if the search string is in the string
to be searched. Then use negation to return the opposite:

!(/image/).test(myStr)

If you really insist on a regular expression that matches all strings
without the substring "image", then here are some suggestions:

Using lookahead:
/^((?!image).)*$/
(probably horribly inefficient with all that lookahead)

Brute force:
/^([^i]*)((i[^im]|i$|im[^ia]|im$|ima[^ig]|ima$|imag[^ie]|imag$)[^i]*)*$/

Combination, only do lookahead on an i.
/^([^i]*)((i(?!mage))*[^i]*)*$/

Enjoy
/L

 

[Larry Woods]

Lookahead works great!

Using lookahead:
/^((?!image).)*$/
(probably horribly inefficient with all that lookahead)

I am using it in a vb.net application any it's "instantaneous!" (600 record
file)

Thanks.

Larry

I want a regular expression that will return TRUE if there is NOT a
substring in the string. Example: Return true if the substring "image" is
NOT in the string.

That is hard.

It is much easier to return true if the search string is in the string
to be searched. Then use negation to return the opposite:

!(/image/).test(myStr)

If you really insist on a regular expression that matches all strings
without the substring "image", then here are some suggestions:

Using lookahead:
/^((?!image).)*$/
(probably horribly inefficient with all that lookahead)

Brute force:
/^([^i]*)((i[^im]|i$|im[^ia]|im$|ima[^ig]|ima$|imag[^ie]|imag$)[^i]*)*$/

Combination, only do lookahead on an i.
/^([^i]*)((i(?!mage))*[^i]*)*$/

Enjoy
/L