How to initialize a string with not using escape?

[Peng Yu]

Suppose I have backslash in the following code, backslash will be
interpreted as the escape character to change the meaning of the next
character. But I don't what such changes. Besides using double
backslashes, is there a way make C++ compiler take backslash
literally?

std::string s="\a\&^";

 

[Richard]

[Please do not mail me a copy of your followup]

Peng Yu <[email protected]> spake the secret code

[...] Besides using double
backslashes, is there a way make C++ compiler take backslash
literally?

Not in a string literal, no.

 

[red floyd]

[Please do not mail me a copy of your followup]

Peng Yu <[email protected]> spake the secret code

[...] Besides using double
backslashes, is there a way make C++ compiler take backslash
literally?

Not in a string literal, no.

Well, in C++0x, he could use a raw string literal, couldn't he?

 

[Richard]

[Please do not mail me a copy of your followup]

red floyd <[email protected]> spake the secret code

[Please do not mail me a copy of your followup]

Peng Yu <[email protected]> spake the secret code

[...] Besides using double
backslashes, is there a way make C++ compiler take backslash
literally?

Not in a string literal, no.

Well, in C++0x, he could use a raw string literal, couldn't he?

Didn't know that was in C++0x. Still, considering that it isn't in gcc
or VC++, I don't know that its very useful (yet).

<http://www.aristeia.com/C++0x/C++0xFeatureAvailability.htm>

 

[Jorgen Grahn]

Peng Yu <[email protected]> spake the secret code
<1da334ed-373c-47ba-8025-bb56176f1...@c33g2000yqm.googlegroups.com> thusly:

[...] Besides using double
backslashes, is there a way make C++ compiler take backslash
literally?

Not in a string literal, no.

Well, in C++0x, he could use a raw string literal, couldn't he?

Didn't know that was in C++0x. Still, considering that it isn't in gcc
or VC++, I don't know that its very useful (yet).

<http://www.aristeia.com/C++0x/C++0xFeatureAvailability.htm>

Also worth keeping in mind is that *when* such a thing becomes
available, it takes years or decades until many of us can use them.

Earlier today, I had to rewrite a piece of C99 code (ten years ago) as
C89 (twenty years ago) because at least one of our compilers hadn't
heard of declaring variables at any place except the top of a block.
Very annoying!

/Jorgen

 

[Michael Tsang]

red floyd <[email protected]> spake the secret code

On Jun 13, 8:52 pm, (e-mail address removed) (Richard) wrote:
Peng Yu <[email protected]> spake the secret code
<1da334ed-373c-47ba-8025-bb56176f1...@c33g2000yqm.googlegroups.com>
thusly:

[...] Besides using double
backslashes, is there a way make C++ compiler take backslash
literally?

Not in a string literal, no.

Well, in C++0x, he could use a raw string literal, couldn't he?

Didn't know that was in C++0x. Still, considering that it isn't in gcc
or VC++, I don't know that its very useful (yet).

<http://www.aristeia.com/C++0x/C++0xFeatureAvailability.htm>

Also worth keeping in mind is that *when* such a thing becomes
available, it takes years or decades until many of us can use them.

Earlier today, I had to rewrite a piece of C99 code (ten years ago) as
C89 (twenty years ago) because at least one of our compilers hadn't
heard of declaring variables at any place except the top of a block.
Very annoying!

/Jorgen

Are you writing a compiler? If not, just tell the user to compile a C99
compiler.

 

[Jorgen Grahn]

Jorgen Grahn wrote: ....


Are you writing a compiler? If not, just tell the user to compile a C99
compiler.

Welcome to the real world! If you have never got stuck in a situation
like that it can be hard to understand, but combine these:

- lack of time to do "cosmetic" work
- fear of regressions in rarely-used code which is hard to test
- semi-obsolete embedded systems
- ... with semi-obsolete toolchains
- ... which are shared with other projects
- inflexible build systems with hardcoded dependencies

and it's not really /that/ surprising that you end up with an ancient
dialect of (in this case) C.

/Jorgen