How to see the __name__ attribute of a class by using dir()

[Jennie]

The dir() built-in does not show the __name__ attribute of a class:
'Foo'

I implementd my custom __dir__, but the dir() built-in do not want to
call it:
.... @classmethod
.... def __dir__(cls):
.... return ['python']
....

Foo.__dir__() ['python']
dir(Foo)

['__class__', '__delattr__', '__dict__', ...]

Can someone tell me where is the problem? Thanks a lot in advance

 

[Peter Otten]

The dir() built-in does not show the __name__ attribute of a class:
'Foo'

I implementd my custom __dir__, but the dir() built-in do not want to
call it:
... @classmethod
... def __dir__(cls):
... return ['python']
...

Foo.__dir__() ['python']
dir(Foo)

['__class__', '__delattr__', '__dict__', ...]

Can someone tell me where is the problem? Thanks a lot in advance

Implementing __dir__ as an instance method works:
.... def __dir__(self): return ["python"]
....['python']

So if you want to customise dir(Foo) you have to modify the metaclass:
.... class __metaclass__(type):
.... def __dir__(self): return ["python"]
....['python']

 

[Jennie]

So if you want to customise dir(Foo) you have to modify the metaclass:
... class __metaclass__(type):
... def __dir__(self): return ["python"]
...['python']

Hi Peter, thanks for your answer, but it does not work (Python 3.3):
.... class __metaclass__(type):
.... def __dir__(self): return ["python"]
....['__class__', '__delattr__', '__dict__', '__dir__', ...]

Regards,

 

[Jennie]

So if you want to customise dir(Foo) you have to modify the metaclass:
... class __metaclass__(type):
... def __dir__(self): return ["python"]
...['python']

Hi Peter, thanks for your answer, but it does not work (Python 3.3):
.... class __metaclass__(type):
.... def __dir__(self): return ["python"]
....['__class__', '__delattr__', '__dict__', '__dir__', ...]

Regards,

 

[Peter Otten]

So if you want to customise dir(Foo) you have to modify the metaclass:

class Foo:

... class __metaclass__(type):
... def __dir__(self): return ["python"]
...

dir(Foo)

['python']

Hi Peter, thanks for your answer, but it does not work (Python 3.3):
... class __metaclass__(type):
... def __dir__(self): return ["python"]
...['__class__', '__delattr__', '__dict__', '__dir__', ...]

In Python 3 the way to specify the metaclass has changed:
.... def __dir__(self): return ["python"]
........ pass
....['python']

 

[Jennie]

In Python 3 the way to specify the metaclass has changed:
... def __dir__(self): return ["python"]
...... pass
...['python']

Thanks!

 

[Jennie]

In Python 3 the way to specify the metaclass has changed:
... def __dir__(self): return ["python"]
...... pass
...['python']

Thanks!