How to shrink a stringstream

[Medi Montaseri]

Given a stringstream object (tokens) containing
tokens << "token1 token2 token3 token4"

I'd like to extract the first token, which I do by saying

tokens >> token ; // where token is a string

And then pass the remaining portion down to a function.
If I just pass the tokens (even after removing one item from it)
to my function, I see that the entire payload is passed down.

How do I pass the remaining portion down to a function ?
ie "token2 token3 token4"

Thanks

 

[Mike Wahler]

Given a stringstream object (tokens) containing
tokens << "token1 token2 token3 token4"

I'd like to extract the first token, which I do by saying

tokens >> token ; // where token is a string

And then pass the remaining portion down to a function.
If I just pass the tokens (even after removing one item from it)
to my function, I see that the entire payload is passed down.

How do I pass the remaining portion down to a function ?
ie "token2 token3 token4"

It would be better if you posted *compilable* code,
so we know for sure what's wrong.

Example:

#include <iostream>
#include <sstream>

void foo(std::stringstream& ss)
{
std::string tok;

while(ss >> tok)
std::cout << tok << '\n';
}

int main()
{
std::stringstream tokens("token1 token2 token3 token4");
std::string token;
tokens >> token;
foo(tokens);
return 0;

}

Output:

token2
token3
token4

HTH,
-Mike

 

[Medi Montaseri]

It would be better if you posted *compilable* code,
so we know for sure what's wrong.

Example:

#include <iostream>
#include <sstream>

void foo(std::stringstream& ss)
{
std::string tok;

while(ss >> tok)
std::cout << tok << '\n';
}

int main()
{
std::stringstream tokens("token1 token2 token3 token4");
std::string token;
tokens >> token;
foo(tokens);
return 0;

}

Output:

token2
token3
token4

HTH,
-Mike

I must have been sleepy (or even sleeping) last night....you are 100% correct...
it works as expected....sorry for the false alarm....