i want to know what the following function is doing?

[amit129]

hi,

Please tell me what the below mentined code is doing? If i pass String
s as my name is "xyz. and " i am writing . what should be the output.

Thanks in advance

void parse(Block<String>& f, String s)
{
int inquote = 0;
int nf = 0;
int start = -1;
for(int i = 0; i <= length(s); i++){
if(i == length(s) || (isspace(s) && !inquote) || (s == '"' &&
inquote)){
if(start != -1){
nf++;
f.reserve(nf);
if(inquote && i != length(s))
f[nf-1] = s(start,i-start+1);
else
f[nf-1] = s(start,i-start);
start = -1;
inquote = 0;
}
}
else if(start == -1){
start = i;
inquote = (s == '"');
}
}
f.size(nf);
}

Amit

 

[Jens Thoms Toerring]

Please tell me what the below mentined code is doing? If i pass String
s as my name is "xyz. and " i am writing . what should be the output.

void parse(Block<String>& f, String s)

Why don't you put it into a simple program and just test what
it does? Moreover, you picked the wrong newsgroup, this one is
for C, not C++. The experts for C++ are on the other side of
the hallway in comp.lang.c++.
Regards, Jens

 

[Szabolcs Borsanyi]

hi,

Please tell me what the below mentined code is doing? If i pass String
s as my name is "xyz. and " i am writing . what should be the output.

Thanks in advance

void parse(Block<String>& f, String s)

Uups, you forgot to append a ++ to the newsgroup name. And please
resist the temptation to think that C++ is C. Beleive or not,
even your innocent looking '"' has very different meanings in the
two languages, so the advice we could give will probably not apply to you
problem.

Szabolcs