{} in assignment

[slashman]

I recently came across code that looked like this

float i = {1.0};

Can anyone tell me the significances of the curly braces{}.
Thanks in advance
Vivek

 

[santosh]

I recently came across code that looked like this

float i = {1.0};

Can anyone tell me the significances of the curly braces{}.
Thanks in advance
Vivek

It's redundant for this particular initialisation, but if i were to be
an array of float then you'd need the curly braces to initialise one or
more of it's elements. Ex:

float arr[5] = { 1.0, 2.0, 3.0 };

Elements arr[0], arr[1] and arr[2] are initialised with 1.0, 2.0 and 3.0
respectively while the remaining elements are set to zero by the
compiler. This is true only for statically allocated arrays.

 

[Andrey Tarasevich]

I recently came across code that looked like this

float i = {1.0};

Can anyone tell me the significances of the curly braces{}.

There's no "assignment" in your code. This is _initialization_, not
assignment. The initializer is enclosed in '{}'. Initializers enclosed
in '{}' are normally used with aggregates. However, it is perfectly
legal to use '{}'-enclosed initializers with scalar objects, in which
case the '{}' are simply redundant. They don't mean anything, meaning
that your code is the exact equivalent of

float i = 1.0;

The ability to use '{}' in scalar initializers might be useful in
"generic" code (in macros, for example), where you can use the common '=
{ 0 }' initialization idiom with a wider range of types.