inheritage: possible to call the original function ?

[mandatory]

hi,

i have two classes:

class A
{
public:
virtual Push (void *p);

};

And the other one:

Class B : Public A
{
public:
virtual Push (void *p);
}


What i want to do in the Push() in class B, is that i want to do some
additional checking in the start of the function - and the i would like to
call the original code for Push().

Is that possible, can i somehow call the original Push() (the one definded
in ClassA) ? the problem im facing is ofcourse, that when i overrides the
code for Push() it will override it all, so i have to duplicate the code if
i want it to work.

Hope you can understand - and hope you can help - thanks

 

[Alf P. Steinbach]

* mandatory:

class A
{
public:
virtual Push (void *p);

};

And the other one:

Class B : Public A
{
public:
virtual Push (void *p)

{
A:ush( p );
}

 

[Karl Heinz Buchegger]

hi,

i have two classes:

class A
{
public:
virtual Push (void *p);

};

And the other one:

Class B : Public A
{
public:
virtual Push (void *p);
}

What i want to do in the Push() in class B, is that i want to do some
additional checking in the start of the function - and the i would like to
call the original code for Push().

Is that possible, can i somehow call the original Push() (the one definded
in ClassA) ?

Yep.

void B:ush( void* p)
{
...
A:ush( p );
}

 

[mandatory]

"Alf P. Steinbach

{
A:ush( p );
}

Thanx alot Alf