Inheritence and function overloading

[ambarish.mitra]

Class A has a public method f, and another class B is publicly derived
from A. The derived class B has also the same function but with
different arguments.

Question: In the scope of class B, is the function f overloaded? (yes/
no)


class A
{
public: int f(int x);
}

class B: public A
{
public: int f(int x, float y);
}

 

[Kira Yamato]

Class A has a public method f, and another class B is publicly derived
from A. The derived class B has also the same function but with
different arguments.

Question: In the scope of class B, is the function f overloaded? (yes/
no)


class A
{
public: int f(int x);
}

class B: public A
{
public: int f(int x, float y);
}

To see if it is overloaded or not, why not try to write some code to test it?

More specifically, try invoking f(1) and f(1,1.) on an B object.

 

[ltcmelo]

Class A has a public method f, and another class B is publicly derived
from A. The derived class B has also the same function but with
different arguments.

Question: In the scope of class B, is the function f overloaded? (yes/
no)

class A
{
public:    int f(int x);

}

class B: public A
{
public:  int f(int x, float y);



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- Show quoted text -

Hi.

In this case it's not an overload because the implementation in B
hides the implementation in A. Basically, C++ lookup rules will try to
find the symbol in class B. Since it'll find it, class A won't be
looked up.


Leandro Melo