Is 1.8.2 imminent? And detecting Rubyx version

[Andrew Walrond]

I'm holding off an 'official' release of Rubyx (ruby based linux distro)
because it hits some bugs in 1.8.1 which have been fixed in cvs

I was wondering whether anyone knows when 1.8.2 will be released?

Otherwise, is there a way of detecting a version of ruby, which also covers
dated stable snapshots?

Eg Rubyx needs stable-snapshot-2004-01-14.rar or newer. How can I test for it?

Andrew Walrond

 

[Andrew Walrond]

That should have said 'detecting _ruby_ version'

 

[Mauricio Fernández]

I'm holding off an 'official' release of Rubyx (ruby based linux distro)
because it hits some bugs in 1.8.1 which have been fixed in cvs

I was wondering whether anyone knows when 1.8.2 will be released?

Otherwise, is there a way of detecting a version of ruby, which also covers
dated stable snapshots?

Eg Rubyx needs stable-snapshot-2004-01-14.rar or newer. How can I test for it?

VERSION and RUBY_RELEASE_DATE

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Running Debian GNU/Linux Sid (unstable)
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And Bruce is effectively building BruceIX
-- Alan Cox

 

[nobu.nokada]

Hi,

At Fri, 6 Feb 2004 19:03:58 +0900,
Mauricio Fernández wrote in [ruby-talk:91687]:

VERSION and RUBY_RELEASE_DATE

VERSION is already obsolete and no longer available in 1.9, use
RUBY_VERSION instead.

 

[Andrew Walrond]

VERSION and RUBY_RELEASE_DATE

Thanks! My implementation seems messy though. Can anybody think of how to
clean it up?


#Need ruby 1.8.1 stable snapshot >= 2004-01-14
catch k do
puts("Detected ruby version #{VERSION}, released #{RUBY_RELEASE_DATE}")
VERSION =~ /(\d*).(\d*).(\d*)/
v1,v2,v3 = $1.to_i,$2.to_i,$3.to_i
RUBY_RELEASE_DATE =~ /(\d*)-(\d*)-(\d*)/
d1,d2,d3 = $1.to_i,$2.to_i,$3.to_i
throw k if v1 > 1 or (v1 == 1 and v2 > 8) or (v1 == 1 and v2 == 8 and v3

1)

if v1 == 1 and v2 == 8 and v3 == 1
throw k if d1 > 2004 or (d1 == 2004 and d2 > 1) or (d1 == 2004 and d2
== 1 and d3 > 13)
end
raise "Rubyx needs ruby version 1.8.2 or a 1.8.1 stable snapshot released
after 2004-02-13"
end

 

[Andrew Walrond]

VERSION is already obsolete and no longer available in 1.9, use
RUBY_VERSION instead.

Thanks for that. I'll make the change

 

[Robert Klemme]

Maybe this old posting (Nov 25th 2003) of mine helps:

A bit more complicated, but could be included in the std. distribution...

module Kernel
def ensure_version( ver )
if ( RUBY_VERSION.split(/\./).map{|x|x.to_i} <=>
ver.split(/\./).map{|x|x.to_i} ) < 0
throw "Version error: should be #{ver} but is #{RUBY_VERSION}"
end
end
end

ensure_version "1.7.0"
ensure_version "1.8.0"
ensure_version "1.8.1"

Kind regards

robert

 

[nobu.nokada]

Hi,

At Fri, 6 Feb 2004 19:42:54 +0900,
Andrew Walrond wrote in [ruby-talk:91690]:

Thanks! My implementation seems messy though. Can anybody think of how to
clean it up?


#Need ruby 1.8.1 stable snapshot >= 2004-01-14

case RUBY_VERSION <=> "1.8.1"
when 1 then true
when 0 then RUBY_RELEASE_DATE >= "2004-01-14"
end or raise "Need ruby 1.8.1 stable snapshot >= 2004-01-14"

 

[Andrew Walrond]

case RUBY_VERSION <=> "1.8.1"
when 1 then true
when 0 then RUBY_RELEASE_DATE >= "2004-01-14"
end or raise "Need ruby 1.8.1 stable snapshot >= 2004-01-14"

Smart-arse

Thanks!

 

[Han Holl]

Hi,

irb(main):001:0> "1.12.3" <=> "1.8.0"
=> -1

Does ruby guarantee never to use two-digit version and release
numbers. If not, your comparison method will fail.

Cheers,

Han Holl

 

[nobu.nokada]

Hi,

At Sun, 8 Feb 2004 19:15:00 +0900,
Han Holl wrote in [ruby-talk:91781]:

Does ruby guarantee never to use two-digit version and release
numbers. If not, your comparison method will fail.

Yes, guaranteed.

 

[Yukihiro Matsumoto]

Hi,

In message "Re: Is 1.8.2 imminent? And detecting Rubyx version"

|Does ruby guarantee never to use two-digit version and release
|numbers. If not, your comparison method will fail.

We will never use two digit version. Don't worry.

matz.