B
Barry Schwarz
Ok I'll try this that's not random. p 143 ¶ 3 §6.6.
for(hashval=0;*s!='\0';s++)
One of your problems is that it is on page 144, not 143. It is
section 6.6 but I have no idea what the "¶ 3" is supposed to
represent.
Why is *s not just s? This speaks of arrays. When I think of linked lists I
don't think of arrays except arrays of structs. I will work with nlist,
lookup, and install and try to figure them out. It might work. But do I
understand what I'm doing? I guess I'll see.
Good to see you take the advice against guessing seriously. And the
answer to your question is obviously no.