logic ops,

[vsgdp]

bool a =false;
bool b=true;
cout << (a || b) && false;
cout.operator <<((a || b) && false);

The first cout outputs true. The second one false. Why not both false?

 

[Marcus Kwok]

bool a =false;
bool b=true;
cout << (a || b) && false;
cout.operator <<((a || b) && false);

The first cout outputs true. The second one false. Why not both false?

Order of operations. The first one does "cout << (a || b)" first, which
returns a reference to the stream (cout). Then it does "cout && false"
and discards the result.

It should do what you think if you add an extra set of parentheses:

cout << ((a || b) && false);