max value in list

[C GIllespie]

Dear all,

I have a few lists. What's the best way of finding the maximum number of all
the lists.

For example,

[2,3,4],[1,2,3],[4,7]

The max is 7.

Thanks

Colin

 

[Terry Reedy]

Dear all,

I have a few lists. What's the best way of finding the maximum number of all
the lists.

For example,

[2,3,4],[1,2,3],[4,7]

The max is 7.

Sidestepping 'best' which may depend on context, a general 'good' way is

lists = [2,3,4],[1,2,3],[4,7]
max([max(l) for l in lists])

7

Terry J. Reedy

 

[Jean Brouwers]

[[ This message was both posted and mailed: see
the "To," "Cc," and "Newsgroups" headers for details. ]]


What about:

m = max([max(i) for i in (list1, list2, list3, etc...)])

Example:

max([max(i) for i in ([2,3,4], [1,2,3], [4,7])])

7

/Jean Brouwers
ProphICy Semiconductor, Inc.

Dear all,

I have a few lists. What's the best way of finding the maximum number of all
the lists.

For example,

[2,3,4],[1,2,3],[4,7]

The max is 7.

Thanks

Colin

 

[Peter Abel]

Dear all,

I have a few lists. What's the best way of finding the maximum number of all
the lists.

For example,

[2,3,4],[1,2,3],[4,7]

The max is 7.

Thanks

Colin

l=[[2, 3, 4], [1, 2, 9], [4, 7]]
max(map(max,l)) 9
l=[[2, 3, 4], [1, 2, 9],[12], [4, 7]]
max(map(max,l)) 12

Regards
Peter

 

[Peter Otten]

I have a few lists. What's the best way of finding the maximum number of
all the lists.

For example,

[2,3,4],[1,2,3],[4,7]

The max is 7.

For arbitrarily nested sequences:
.... try:
.... return max(map(rmax, seq))
.... except TypeError:
.... return seq
....

rmax(1) 1
rmax([1,2]) 2
rmax([[1,2], [3,4]]) 4
rmax([[1,2], [3,44], 5, [6]]) 44
rmax([[1,2], [[3,44], 5, [6]]]) 44

Peter

 

[Duncan Booth]

Sidestepping 'best' which may depend on context, a general 'good' way is

lists = [2,3,4],[1,2,3],[4,7]
max([max(l) for l in lists])

7

Without any claims to better or worse, here is another option:

l = [2,3,4],[1,2,3],[4,7]
l ([2, 3, 4], [1, 2, 3], [4, 7])
max(itertools.chain(*l)) 7

 

[C GIllespie]

Dear All,

Thanks for all the responses.

Very helpful (again)

Colin