Module for creating a screenshot of a web page given a URL?

[dananrg]

Is there a Python module that, given a URL, will grab a screenshot of
the web page it goes to? I'd like to be able to feed such a module a
list of URLs from a file.

Thanks very much.

 

[Rune Strand]

Is there a Python module that, given a URL, will grab a screenshot of
the web page it goes to? I'd like to be able to feed such a module a
list of URLs from a file.

Thanks very much.

Not as I know of, but it's easy to write

Something like this quasi-code:

import time,webbrowser
from PIL import ImageGrab

list_of_urls = [''http://www.google.com', 'http://www.egg.net']

for url in list_of_urls:
webbrowser.open(url)
time.sleep(5) # wait for it to load
screen = ImageGrab.grab(coords etc)
screen.save(some_name_in_some_path)

Untestetd, but I'm pretty sure something like this will do.
If you need more control, and on windows, try pywinauto

 

[dananrg]

Untestetd, but I'm pretty sure something like this will do.

If you need more control, and on windows, try pywinauto

I do need it to run on Windows. I'll check out pywinauto. Thanks.

 

[John J. Lee]

I do need it to run on Windows. I'll check out pywinauto. Thanks.

Note he didn't say you *need* pywinauto to run on Windows.


John

 

[chemila66]

Note he didn't say you *need* pywinauto to run on Windows.


John

Is there anyway to do the same job in linux?
The ImageGrab doesn't support for linux system.

If anyone knows that, please, reply me. Thanks a lot.