my last question tonight... s///

[Guy]

I have a list of number like 001, 002, 003, ... 100, in my first field. I
want to remove the leading zeros. Should I do:

$a = $field[0] + 0; # this appears to work

or

($a = $field[0]) =~ s/^0+//; # this also appears to work.

or is there yet a better way?
Guy

 

[sln]

I have a list of number like 001, 002, 003, ... 100, in my first field. I
want to remove the leading zeros. Should I do:

$a = $field[0] + 0; # this appears to work

or

($a = $field[0]) =~ s/^0+//; # this also appears to work.

or is there yet a better way?
Guy

Why do anything. Its both a string and a number.
Its how you use it. If you want to print it as a
number use printf "%d",$a otherwise use printf "%s", $a.
The trick is to be specific, think of it as a coersion.

-sln

 

[sln]

I have a list of number like 001, 002, 003, ... 100, in my first field. I
want to remove the leading zeros. Should I do:

$a = $field[0] + 0; # this appears to work

or

($a = $field[0]) =~ s/^0+//; # this also appears to work.

or is there yet a better way?
Guy

Why do anything. Its both a string and a number.
Its how you use it. If you want to print it as a
number use printf "%d",$a otherwise use printf "%s", $a.
The trick is to be specific, think of it as a coersion.

But if it bothers you, s/^0+// is what you want.

-sln

 

[Ben Bullock]

I have a list of number like 001, 002, 003, ... 100, in my first field. I
want to remove the leading zeros. Should I do:

$a = $field[0] + 0; # this appears to work

or

($a = $field[0]) =~ s/^0+//; # this also appears to work.

or is there yet a better way?

Another way to do it is $a = int $field[0].

Which way is "better" depends what you mean by better - easier to read,
faster, more compact, etc.