Newby Q: nested classes, access of upper method

[Gregor Horvath]

Hello,

class A(self):
def A1():
pass

class B(self):
def B1():
#************************************
#*** How can I access A1 here???? ***
#************************************
self.A1() # doesnet work because self references to B
self.self.A1() #doesnt work either


Renanimg class B(self1): doesnt work either because self is not bound.

How can I access a method of a "upper" class?

 

[Nick Coghlan]

Hello,

class A(self):
def A1():
pass

class B(self):
def B1():
#************************************
#*** How can I access A1 here???? ***
#************************************
self.A1() # doesnet work because self references to B
self.self.A1() #doesnt work either


Renanimg class B(self1): doesnt work either because self is not bound.

OK, I suspect you're a little confused about how classes work. The items in
brackets after a class name are the *base* classes of a class, not the way the
class refers to itself. So Python will complain if the listed items can't be
inherited from for one reason or another.

I suggest having another read of the tutorial section on classes to figure out
exactly what you want to be doing:
http://www.python.org/doc/2.3.4/tut/node11.html

How can I access a method of a "upper" class?

Merely defining one class inside another class does not automatically give
instances of that inner class a reference to an instance of the outer class - if
such a reference is needed, it must be provided in the inner class's constructor.

E.g.

class A(object):
class B(object):
def __init__(self, owner):
self._owner = owner

def B1(self):
self._owner.A1()

def A1(self):
pass

def makeB(self):
return A.B(self)

Cheers,
Nick.

 

[Gregor Horvath]

Hello Nick,

thank you, your answer really helped me..