os.system(cmd) isn't working

[=?ISO-8859-1?Q?Gregory_Pi=F1ero?=]

Hi guys,

I'm trying to run this statement:

os.system(r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"')

The goal is to have firefox open to that website.

When I type r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"' in the python interpreter I get:

'"C:\\Program Files\\Mozilla Firefox\\firefox.exe"
"www.blendedtechnologies.com"'

And when I copy this into my command prompt (less outermost ' )
firefox opens up to that page like I would expect. However in python
nothing happens and I get exit status 1.

I'm using Python 2.3 on Windows XP pro service pack 2.

I'd greatly appriciate any help.

Thanks,

Greg

 

[Paul Watson]

Hi guys,

I'm trying to run this statement:

os.system(r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"')

The goal is to have firefox open to that website.

When I type r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"' in the python interpreter I get:

'"C:\\Program Files\\Mozilla Firefox\\firefox.exe"
"www.blendedtechnologies.com"'

And when I copy this into my command prompt (less outermost ' )
firefox opens up to that page like I would expect. However in python
nothing happens and I get exit status 1.

I'm using Python 2.3 on Windows XP pro service pack 2.

I'd greatly appriciate any help.

Thanks,

Greg

===============
These seemed to work on one machine for Python 2.1 and 2.4.
1

 

[F. Petitjean]

Le Thu, 23 Jun 2005 01:19:11 -0500, Paul Watson a écrit :

Hi guys,

I'm trying to run this statement:

os.system(r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"')

The goal is to have firefox open to that website.

I suggest to use the subprocess module. You don't have insert " around a
path with embedded spaces and you can give the exact executable
pathname, set the directory for the child process, etc

import os
import os.path
import subprocess
path_exe = r'C:\Program Files\Mozilla Firefox\firefox.exe'
assert os.path.exists(path_exe)
url = "http://www.blendedtechnologies.com"
child = subprocess.Popen( (path_exe, url), executable = path_exe)
rc = child.wait()

I'm using Python 2.3 on Windows XP pro service pack 2.

I think that subprocess is a new Python2.4 module, but you should be
able to find a 2.3 version (perhaps effbot.org)

 

[Tjarko de Jong]

Hi guys,

I'm trying to run this statement:

os.system(r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"')

The goal is to have firefox open to that website.

When I type r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"' in the python interpreter I get:

'"C:\\Program Files\\Mozilla Firefox\\firefox.exe"
"www.blendedtechnologies.com"'

And when I copy this into my command prompt (less outermost ' )
firefox opens up to that page like I would expect. However in python
nothing happens and I get exit status 1.

I'm using Python 2.3 on Windows XP pro service pack 2.

What is wrong with:
os.startfile("www.blendedtechnologies.com")

 

[Dennis Lee Bieber]

Hi guys,

I'm trying to run this statement:

os.system(r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"')

The goal is to have firefox open to that website.

Assuming Firefox is the default browser, and you are on windows
(as the C:\ indicates):

worked on my system -- but you probably /need/ to include the http
protocol prefix.


--

 

[drobinow]

If firefox is not your default browser,
os.system(r'"cd c:\Program Files\Mozilla Firefox & firefox "' +
'"www.blendertechnologies.com"')

works for me.

 

[=?ISO-8859-1?Q?Gregory_Pi=F1ero?=]

Thanks to everyone for all the help! After careful consideration I
decided to go with os.startfile(url)

It works just great!

Here's my program in case anyone's interested. 5 points if you can
guess what it does ;-)

"""Take a filepath from stdin and translate to the corresponding url and
open up browser and show it."""
import sys
import os
myhtmlroot='C:\\Documents and Settings\\Gregory\\My
Documents\\blendedtechnologies\\trunk'
htmlroot='http://www.blendedtechnologies.com'
filepath=sys.argv[1]
filename=os.path.basename(filepath)
filedir=os.path.dirname(filepath).replace(myhtmlroot,'').replace('\\','/')
url=htmlroot+'/'+filedir+'/'+filename
os.startfile(url)


-Greg

 

[Terry Hancock]

os.system(r'"C:\Program Files\Mozilla Firefox\firefox.exe"' + '
"www.blendedtechnologies.com"')

The goal is to have firefox open to that website.

You don't have any spaces between the command and the argument,
I would assume they'd be necessary. I also notice you are quoting
the quotes here, so I presume you actually need them (maybe this is
because you have an embedded space in the filename?).

Need I mention that using filenames with spaces is a great evil? ;-)

 

[Peter Hansen]

You don't have any spaces between the command and the argument,

I spent a while trying to prove that to myself as well, but eventually I
concluded that the fact that the ' and the " after the plus sign are on
separate lines must mean that there was whitespace between them, or the
line break would have occurred before the ' ... but it did seem like a
good theory while it lasted. ;-)

-Peter