D
danil52
Hello there,
I have the following code:
class Base {
public:
virtual void f() {cout << "Base::f()" << endl;}
virtual void f(int) {cout << "Base::f(int)" << endl;}
};
class Derived : public Base {
void f() {cout << "Derived::f()" << endl;}
};
int main() {
Base *ptr = new Derived();
ptr->f();
ptr->f(1);
return 0;
}
As you can see, I overridden Base::f() from public, to private access
permission. Being the Java guy that I am, I expected a compiler error.
But to my surprise, the program ran fine, and called the private
version? Is this a compiler bug (I use g++), or is the function
explicitly converted to public? Thank you.
I have the following code:
class Base {
public:
virtual void f() {cout << "Base::f()" << endl;}
virtual void f(int) {cout << "Base::f(int)" << endl;}
};
class Derived : public Base {
void f() {cout << "Derived::f()" << endl;}
};
int main() {
Base *ptr = new Derived();
ptr->f();
ptr->f(1);
return 0;
}
As you can see, I overridden Base::f() from public, to private access
permission. Being the Java guy that I am, I expected a compiler error.
But to my surprise, the program ran fine, and called the private
version? Is this a compiler bug (I use g++), or is the function
explicitly converted to public? Thank you.