pointers to char

[gordy]

Newbie question, please by gentle.

I'm trying to read in a text file containing the days of the week, one on
each line. Each line should be pointed to by an array of pointers to char
but I'm ending up with each pointer pointing to the same string.

#include <stdio.h>
#include <stdlib.h>

#define DAYS 7

int main()
{
int count = 0, bytes_read;
char *strings[DAYS], *buffer = NULL;
FILE *fp;
size_t size = 1;

if((fp = fopen("days", "r")) == NULL)
{
puts("File not found");
exit(EXIT_FAILURE);
}

while(bytes_read = (getline(&buffer ,&size, fp)) != -1)
strings[count++] = buffer;

while(count--)
printf("\t\t%s", *(strings + count));

fclose(fp);
return 0;
}

file days:
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Sunday

I'm sure I'm missing something silly here, any help would be appreciated.

gordy.

 

[Kenneth Brody]

Newbie question, please by gentle.

I'm trying to read in a text file containing the days of the week, one on
each line. Each line should be pointed to by an array of pointers to char
but I'm ending up with each pointer pointing to the same string.

#include <stdio.h>
#include <stdlib.h>

#define DAYS 7

int main()
{
int count = 0, bytes_read;
char *strings[DAYS], *buffer = NULL;
FILE *fp;
size_t size = 1;

if((fp = fopen("days", "r")) == NULL)
{
puts("File not found");
exit(EXIT_FAILURE);
}

while(bytes_read = (getline(&buffer ,&size, fp)) != -1)

I don't know what getline() does. While my system has a getline()
function, it is totally different that yours, as mine is prototyped
as:

char *getline(char *prompt);

I am guessing, based on context, that you pass it:

The address of a char* for the buffer. If the pointer is
NULL, then a buffer will be allocated for you.

The address of an int, to return the size of the buffer.

The FILE* stream to read from.

And it returns the number of bytes read.

Continuing with my assumptions, if buffer is not NULL, then it
will use the buffer/length which is passed to it.

strings[count++] = buffer;

If my assumptions above are true, then once the buffer is allocated
for the first call, it will continue using the same buffer, as your
"char *buffer" is no longer NULL.

while(count--)
printf("\t\t%s", *(strings + count));

Is ther any reason you don't use "strings[count]" here? It's much
clearer, at least for me.

fclose(fp);
return 0;
}

file days:
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Sunday

I'm sure I'm missing something silly here, any help would be appreciated.

If any of my assumptions above are wrong, then you are going to have to
describe how your getline() function works.

--
+-------------------------+--------------------+-----------------------------+
| Kenneth J. Brody | www.hvcomputer.com | |
| kenbrody/at\spamcop.net | www.fptech.com | #include <std_disclaimer.h> |
+-------------------------+--------------------+-----------------------------+
Don't e-mail me at: <mailto:[email protected]>

 

[Keith Thompson]

Newbie question, please by gentle.

I'm trying to read in a text file containing the days of the week, one on
each line. Each line should be pointed to by an array of pointers to char
but I'm ending up with each pointer pointing to the same string.

#include <stdio.h>
#include <stdlib.h>

#define DAYS 7

int main()
{
int count = 0, bytes_read;
char *strings[DAYS], *buffer = NULL;
FILE *fp;
size_t size = 1;

if((fp = fopen("days", "r")) == NULL)
{
puts("File not found");
exit(EXIT_FAILURE);
}

while(bytes_read = (getline(&buffer ,&size, fp)) != -1)

getline() is a non-standard function.

strings[count++] = buffer;

This is a pointer assignment. You pass its address to getline(), but
unless getline() changes the value you're assigning the same pointer
value to each element of strings.

You probably want to copy the string using strcpy() -- which means
you also need to allocate memory using malloc() (and don't forget
to check whether malloc() succeeded).

while(count--)
printf("\t\t%s", *(strings + count));

The expression *(strings + count) is better written as strings[count].

 

[gordy]

Newbie question, please by gentle.

I'm trying to read in a text file containing the days of the week, one on
each line. Each line should be pointed to by an array of pointers to char
but I'm ending up with each pointer pointing to the same string.

#include <stdio.h>
#include <stdlib.h>

#define DAYS 7

int main()
{
int count = 0, bytes_read;
char *strings[DAYS], *buffer = NULL;
FILE *fp;
size_t size = 1;

if((fp = fopen("days", "r")) == NULL)
{
puts("File not found");
exit(EXIT_FAILURE);
}

while(bytes_read = (getline(&buffer ,&size, fp)) != -1)

I don't know what getline() does. While my system has a getline()
function, it is totally different that yours, as mine is prototyped
as:

char *getline(char *prompt);

I am guessing, based on context, that you pass it:

The address of a char* for the buffer. If the pointer is
NULL, then a buffer will be allocated for you.

The address of an int, to return the size of the buffer.

The FILE* stream to read from.

And it returns the number of bytes read.

Continuing with my assumptions, if buffer is not NULL, then it
will use the buffer/length which is passed to it.

strings[count++] = buffer;

If my assumptions above are true, then once the buffer is allocated
for the first call, it will continue using the same buffer, as your
"char *buffer" is no longer NULL.

following this advice I changed the code to:

while(bytes_read = (getline(&buffer ,&size, fp)) != -1)
{
strings[count++] = buffer;
buffer = NULL;
}and:
printf("\t\t%s", strings[count]);

Is ther any reason you don't use "strings[count]" here? It's much
clearer, at least for me.

fclose(fp);
return 0;
}

file days:
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Sunday

I'm sure I'm missing something silly here, any help would be appreciated.

If any of my assumptions above are wrong, then you are going to have to
describe how your getline() function works.

Your assumptions were spot on, it's now working as I wanted it to.

many thanks for your help.