J
Jean-Michel Pichavant
To all using xmlrpclib,
I had trouble getting a proper display of my exceptions occuring on the
server. Basically, xmlrpclib only display the exception itself without
any traceback, on the client side.
Something like
<Fault 1: "<type 'exceptions.KeyError'>:2">
Ok then there's a key error, but how the hell am I supposed to know
where it occured ?
So I wrote this:
from SimpleXMLRPCServer import SimpleXMLRPCServer
server = SimpleXMLRPCServer(('localhost', 8000), logRequests=False,
allow_none=True)
old_dispatch = server._dispatch
def _new_dispatch(method, params):
try:
return old_dispatch(method,params)
except Exception, exc:
import traceback
traceback.print_exc()
raise
server._dispatch = _new_dispatch
Pretty dirty, isn't it, accessing the private attributes (too lazy to
subclass) ! I guess there's an obvious way to do this with xmlrpclib
that I just missed. Anyone knows ?
JM
I had trouble getting a proper display of my exceptions occuring on the
server. Basically, xmlrpclib only display the exception itself without
any traceback, on the client side.
Something like
<Fault 1: "<type 'exceptions.KeyError'>:2">
Ok then there's a key error, but how the hell am I supposed to know
where it occured ?
So I wrote this:
from SimpleXMLRPCServer import SimpleXMLRPCServer
server = SimpleXMLRPCServer(('localhost', 8000), logRequests=False,
allow_none=True)
old_dispatch = server._dispatch
def _new_dispatch(method, params):
try:
return old_dispatch(method,params)
except Exception, exc:
import traceback
traceback.print_exc()
raise
server._dispatch = _new_dispatch
Pretty dirty, isn't it, accessing the private attributes (too lazy to
subclass) ! I guess there's an obvious way to do this with xmlrpclib
that I just missed. Anyone knows ?
JM