Question on using urllib

[Olivier Scalbert]

Hello all,

Sorry if this question is not 100% python related, it is also related to
http or html ...

Everything takes place in this page:
http://www.infometeo.be/klanten/KYC/campage2mega.php

With the following program, I can download the 2 small meteo images,
without any problem:

import urllib

urllib.urlretrieve("http://www.infometeo.be/wwweather/currentimage.php?icao=EBFN",
"meteo1.jpg")
urllib.urlretrieve("http://www.meteokust.be/metstatgr.php?s=zb",
"meteo2.jpg")

But I would like to download the main background picture.

By looking inside the html page, it seems it's url is:
http://www.infometeo.be/img.php?iid=1057

....
<table bgcolor="#6699FF">
<tr>
<td>
<table width="1280" height="960"
background="http://www.infometeo.be/img.php?iid=1057">
<tr>
<td align="right" valign="bottom">
....

Warning, the iid may vary depending time ...

I try to download it with python:
urllib.urlretrieve("http://www.infometeo.be/img.php?iid=1057",
"picture.jpg")
But then I receive only 2 bytes: CR LF I think.

If I use this url with my browser (firefox), I also get nothing (a blank
page).
If I go back to the main page with the firebug plugin activated, I can
change the iid directly inside the html code with firebug, and then,
even previous pictures can be displayed ...

So I am a bit lost ... Any help would be very appreciate !!

Thanks,

Olivier

 

[Peter Otten]

Sorry if this question is not 100% python related, it is also related to
http or html ...

Everything takes place in this page:
http://www.infometeo.be/klanten/KYC/campage2mega.php

With the following program, I can download the 2 small meteo images,
without any problem:

import urllib

urllib.urlretrieve("http://www.infometeo.be/wwweather/currentimage.php?icao=EBFN",
"meteo1.jpg")
urllib.urlretrieve("http://www.meteokust.be/metstatgr.php?s=zb",
"meteo2.jpg")

But I would like to download the main background picture.

By looking inside the html page, it seems it's url is:
http://www.infometeo.be/img.php?iid=1057

I try to download it with python:
urllib.urlretrieve("http://www.infometeo.be/img.php?iid=1057",
"picture.jpg")

The problem is indeed not Python-related. The provider of the images doesn't
like what you're trying to do and verifies the referer, i. e. that the page
you claim to be coming from is acceptable. Here's one way to satisfy that
check:

Now if you are using that workaround a lot he may come up with more
sophisticated techniques. So dont

Peter

 

[Olivier Scalbert]

The problem is indeed not Python-related. The provider of the images doesn't
like what you're trying to do and verifies the referer, i. e. that the page
you claim to be coming from is acceptable. Here's one way to satisfy that
check:


Now if you are using that workaround a lot he may come up with more
sophisticated techniques. So dont

Peter

Thanks Peter, it works perfectly !
At 60 fps I can even make a video ...
;-)

Olivier