Sending std::cout to std::cout

[saurabh29789]

I have a statement I'd like you to consider :

std::cout<<(std::cout<<"Hi");

that prints a Hii followed by some address.

The (std::cout<<"Hi") would be returning an object of type ostream,
but what is this address that is printed ?? How??

 

[Tim Slattery]

I have a statement I'd like you to consider :

std::cout<<(std::cout<<"Hi");

that prints a Hii followed by some address.

The (std::cout<<"Hi") would be returning an object of type ostream,
but what is this address that is printed ?? How??

It's printing the address of the std::cout object.

 

[Rolf Magnus]

It's printing the address of the std::cout object.

No. Well, maybe or maybe not. It's printing some address that is not NULL,
because std:stream has a conversion operator to void* that returns a null
pointer if the stream encountered an error or some non-null poiner if it
didn't.