Simple script to make .png thumbnails from .zip archive...

[K P S]

Hi.
I'm looking for a small script that will take a .zip archive and pull
the first .jpg from the archive and convert it to a .png.

The reason for this is I want to have tuhmbnails for these archives in
nautilus under gnome. I would like something similar to the following
code, which will pull a thumbnail from an openoffice.org (oasis)
document. What I want is a little more involved, I guess, since I
don't know the name of the file (for the zip.read command), and I need
to convert the file from .jpg to .png once I get it. Any help would be
appreciated. Including a pointer to a web page of a manual with
examples.

#!/usr/bin/python

import zipfile
import sys
import gnomevfs

inURL=gnomevfs.get_local_path_from_uri(sys.argv[1])
outURL=sys.argv[2]

zip=zipfile.ZipFile(inURL,mode="r")
picture=zip.read("Thumbnails/thumbnail.png")
thumbnail=open(outURL,"w")
thumbnail.write(picture)
thumbnail.write("/n")
zip.close()
thumbnail.close()

 

[hdante]

Hi,

I don't know zipfile by heart, but python official documentation is
always good ( docs.python.org ). You need a loop in the file list like
this:

for file in zip:
process(file)

Unfortunatelly, there are too many ways to create a thumbnail from an
image. I'll cite one, using the "python image" external module, that
I've found to be very easy:

import Image
def process(file):
try:
image = Image.open(file)
image.thumbnail ((128,128), Image.ANTIALIAS)
image.save (file + '.thumb.png')
except:
print 'Skipping file', file

Links:
http://docs.python.org/lib/lib.html - Python Library Reference
http://www.pythonware.com/library/pil/handbook/image.htm - The Image
Module

 

[Scott David Daniels]

.... there are too many ways to create a thumbnail from an
image. I'll cite one, using the "python image" external module, that
I've found to be very easy:

import Image
def process(file):
try:
image = Image.open(file)
image.thumbnail ((128,128), Image.ANTIALIAS)
image.save (file + '.thumb.png')
except:
print 'Skipping file', file

Links:
http://docs.python.org/lib/lib.html - Python Library Reference
http://www.pythonware.com/library/pil/handbook/image.htm - The Image
Module

That, by the way, is the "PIL" library that you'll see a lot about --
The Python Imaging Library that the effbot is justly proud of. You
won't do better than that.

--Scott David Daniels
(e-mail address removed)

 

[K P S]

Thanks a lot.
I'm really new to python, and haven't coded in over a decade, so
please be patient.

I'm able to read a .jpg from a .zip archive, but can't seem to
manipulate it. If I do this:

zip=zipfile.ZipFile(inURL,mode="r")
picture=zip.read("00.jpg")

I get the image, but it is of "type" ZipFile. How can I change it to
type Image? Or am I thinking about this in the wrong way? I would
like to follow this with something like:

picture.thumbnail((128, 128), Image.ANTIALIAS)

But obviously I can't do this directly. What am I missing?

Hi,

I don't know zipfile by heart, but python official documentation is
always good ( docs.python.org ). You need a loop in the file list like
this:

for file in zip:
process(file)

Unfortunatelly, there are too many ways to create a thumbnail from an
image. I'll cite one, using the "python image" external module, that
I've found to be very easy:

import Image
def process(file):
try:
image = Image.open(file)
image.thumbnail ((128,128), Image.ANTIALIAS)
image.save (file + '.thumb.png')
except:
print 'Skipping file', file

Links:
http://docs.python.org/lib/lib.html - Python Library Reference
http://www.pythonware.com/library/pil/handbook/image.htm - The Image
Module

Hi.
I'm looking for a small script that will take a .zip archive and pull
the first .jpg from the archive and convert it to a .png.

The reason for this is I want to have tuhmbnails for these archives in
nautilus under gnome. I would like something similar to the following
code, which will pull a thumbnail from an openoffice.org (oasis)
document. What I want is a little more involved, I guess, since I
don't know the name of the file (for the zip.read command), and I need
to convert the file from .jpg to .png once I get it. Any help would be
appreciated. Including a pointer to a web page of a manual with
examples.

#!/usr/bin/python

import zipfile
import sys
import gnomevfs

inURL=gnomevfs.get_local_path_from_uri(sys.argv[1])
outURL=sys.argv[2]

zip=zipfile.ZipFile(inURL,mode="r")
picture=zip.read("Thumbnails/thumbnail.png")
thumbnail=open(outURL,"w")
thumbnail.write(picture)
thumbnail.write("/n")
zip.close()
thumbnail.close()

 

[Ant]

Try adapting the other posters example with something like:

import Image, StringIO
zip=zipfile.ZipFile(inURL,mode="r")
picture=zip.read("00.jpg")
image = Image.open(StringIO(picture))
image.thumbnail ((128,128), Image.ANTIALIAS)
image.save (file + '.thumb.png')

I haven't tested it, but something like this should work.

 

[Fredrik Lundh]

I'm able to read a .jpg from a .zip archive, but can't seem to
manipulate it. If I do this:

zip=zipfile.ZipFile(inURL,mode="r")
picture=zip.read("00.jpg")

I get the image, but it is of "type" ZipFile.

string, more likely (zip is a ZipFile object, picture is a string of
bytes). PIL expects a file name or a file object, so you need to use
the StringIO adapter:

picture = zip.read(name) # returns a string
file = StringIO.StringIO(picture) # wrap string in file-like object
image = Image.open(file) # create image object from file-like object

</F>

 

[Fredrik Lundh]

What I want is a little more involved, I guess, since I
don't know the name of the file (for the zip.read command)

the first example on this page shows you how to get the names of all
files in a zip file:

http://effbot.org/librarybook/zipfile.htm

</F>

 

[K P S]

Thanks everyone.

One last thing (I hope).

How can I get the name of just the first file in a zipfile? I see
routines to list all the files in a zip archive, but I don't see any to
list only the first, or only the second, etc. It doesn't look like
zipfile is storing info in a useful array that I can hash into. Or is
it?

Actually, I would like to get the name of the first file with a .jpg
extension, if that's not asking too much.

zip=zipfile.ZipFile("text.zip",mode="r")
picture=zip.read(zip.namelist(0))

This doesn't seem to work. :-(

 

[hdante]

Thanks everyone.

routines to list all the files in a zip archive, but I don't see any to
list only the first, or only the second, etc. It doesn't look like

If you can list all the files, then you can list only the first.
Don't worry about python internal allocation procedures. It will try to
make things in an efficient way. Just make sure your code looks cool.
;-)

zip=zipfile.ZipFile("text.zip",mode="r")
picture=zip.read(zip.namelist(0))

That's because you're using the wrong syntax. -> zip.namelist()[0]

However, I bet that your first file in the zip is not a jpeg file. Do
this, instead:

zip = zipfile.ZipFile('text.zip')
jpeglist = [x for x in zip.namelist() if '.jp' in x]
try:
picture = zip.read(jpeglist[0])
except IndexError:
print 'No jpeg found'

 

[K P S]

Thanks a lot! This is what I ended up with.
(I would like to get rar archive support, but browsing the web it looks
like rar support isn't in any python library (yet)) :-( Anyway, I was
able to use the below code unchanged to create thumbnails in nautilus
based on the first .jpg file in a .zip archive.

Is there any rar support module in python?

Thanks again.


#!/usr/bin/python

import zipfile
import sys
import gnomevfs
import Image
import StringIO

inURL=gnomevfs.get_local_path_from_uri(sys.argv[1])
outURL=sys.argv[2]

zip=zipfile.ZipFile(inURL,mode="r")
jpeglist=[x for x in zip.namelist() if '.jp' in x]
try:
picture=zip.read(jpeglist[0])
except IndexError:
print 'No jpeg found'

zip.close() #close the file, since we no longer have need of it
image = Image.open(StringIO.StringIO(picture)) # create image object
from file-like object
image.thumbnail((128,128),Image.ANTIALIAS) #create the thumbnail
image.save (outURL, "PNG") #output the file in the proper format