Split function for host:port in standard lib

[Michael Ströder]

HI!

Is there a function in the standard lib which can be used to split a
string containg 'hostort' into a tuple (host,port) and also does this
reliably for IPv6 addresses?

Ciao, Michael.

 

[Manuel Ebert]

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AFAIK port names cannot contain any colons, so python2.5's
'hostort' .rsplit(':') should do the job. On < 2.5 you probably
need to do something like
s = addr.rindex(':')
host, port = addr[:s], addr[s+1:]

Best,
Manuel

HI!

Is there a function in the standard lib which can be used to split
a string containg 'hostort' into a tuple (host,port) and also
does this reliably for IPv6 addresses?

Ciao, Michael.

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[Michael Ströder]

Is there a function in the standard lib which can be used to split a
string containg 'hostort' into a tuple (host,port) and also does
this reliably for IPv6 addresses?

>
AFAIK port names cannot contain any colons, so python2.5's 'hostort'
.rsplit(':') should do the job. On < 2.5 you probably need to do
something like
s = addr.rindex(':')
host, port = addr[:s], addr[s+1:]

Manuel, thanks for answering. But I already thought about this approach.
I should have mentioned that I'd like to return None for a missing port
though. Note the :: in the IPv6 addresses.

Examples:
'localhost:389' -> ('localhost',389)
'localhost' -> ('localhost',None)

Examples IPv4 addresses:
'127.0.0.1' -> ('127.0.0.1',None)

Examples IPv6 addresses:
'::1:389' -> ('::1',389)
'::1' -> ('::1',None)

Ciao, Michael.

 

[Hartmut Goebel]

Examples IPv6 addresses:
'::1:389' -> ('::1',389)
'::1' -> ('::1',None)

These are wrong, see http://tools.ietf.org/html/rfc2732 ("Format for
Literal IPv6 Addresses in URL's§).

Correct formats are:
[::1]:389
[::1]