Spliting hash using map!

[Ne Scripter]

Hello,

I have a program which goes through a number of entries, a typical
example of these entries is as follows:

qwerty 0001
abcdef 0002 0003 0004
uvwxyz 0005 0006

Basically, the first string can match to one or more unique numbers.
This structure is a hash. Later in my code I remove the string leaving
only the numbers, I then wish to break the numbers down into their
individual items, I use map! (output = ID.map!{|str| str.split(/\s+/)
}.flatten!) to do this giving

0001
000200030004
00050006

What I want to do at this stage is have them broken into individual
items instead of a full string for each, the purpose of this is so I can
do something like this:

if 0001.match(/#{output}/)
puts output
end

So in a loop for the second entry we would be doing
if 0001.match(/#{0002}/).....
if 0001.match(/#{0003}/) and so on

At this stage I am not getting that result because I do not have 0002,
0003 and so on, I only have individual entries from the hash such as
0001. Could anyone assist me with this query?

Sorry if it is unclear, and may thanks for your help.

 

[Robert Klemme]

Sorry if it is unclear, and may thanks for your help.

I am at a loss here. Can you provide a more complete example which
demonstrates what you're after?

Kind regards

robert

 

[angico]

Hi,

=2D-----

individual items, I use map! (output =3D ID.map!{|str| str.split(/\s+/)
}.flatten!) to do this giving

0001
000200030004
00050006

If you are to put the result of map in 'output' the you don't need map!, ju=
st=20
map. You also don't need flatten!, just flatten.

And, BTW, where does ID come from? What is ID, an array, a string?

=2D-=20
angico
=2D-----

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skype: angico00

 

[Ne Scripter]

Sorry for being unclear.

Basically, if I say the following

string = "0002 0003 0004 0005"

if 0002.match(/#{string}/)
puts string
end

So I want to say if my string contains the item given in the IF
statement tell me the item that it found, in the example above 0002.

The code I have above does not match anything.

Thanks

 

[Ne Scripter]

Solved. I went for string.include?(variable)

Thanks

 

[7stud --]

Sorry for being unclear.

Basically, if I say the following

string = "0002 0003 0004 0005"

if 0002.match(/#{string}/)
puts string
end

So I want to say if my string contains the item given in the IF
statement tell me the item that it found, in the example above 0002.

The code I have above does not match anything.

Your regex is /0002 0003 0004 0005/. That pattern does not appear in
the string "0002" (and the integer 0002 does not have a match()
method!).

Look at this example:

string = "0002 0003 0004 0005"

if string.match(/0002/)
puts string
end

--output:--
0002 0003 0004 0005

In this example, the regex is /0002/, and that patter does occur in the
string "0002 0003 0004 0005", so there is a match.