Substitutions in matched patterns?

[Anton81]

Hi,

what is the easiest way to do substitutions in matched strings.
For example I want to do s/ABC/DEF/g , but only if the ABC is between
braces.

Anton

 

[Paul Lalli]

what is the easiest way to do substitutions in matched strings.
For example I want to do s/ABC/DEF/g , but only if the ABC is between
braces.

http://search.cpan.org
search for Regexp::Common::balanced

Paul Lalli

 

[Anton81]

what is the easiest way to do substitutions in matched strings.

s/{ABC}/{DEF}/g;

ABC is not directly between braces. It's more something like

s/({.*)ABC(.*})/\1DEF\2/g

but as it get's more complicating (more different substitutions), one needs
another solution.

Anton

 

[it_says_BALLS_on_your forehead]

ABC is not directly between braces. It's more something like

s/({.*)ABC(.*})/\1DEF\2/g

but as it get's more complicating (more different substitutions), one needs
another solution.

Actually, backreferences *within* the pattern (in the case of regex
substitution, this is between the first two delimiters) are employed
with a backslash and a digit--like your \1 and \2 for example. However,
if you want to apply your pattern, and then do something with the
captured strings (as is the case with your substitution) you want to
use the $1 form of backreferences, where the '1' is the capture
specified by the first left parens.

See Programming Perl 3rd ed. pg. 183.

 

[it_says_BALLS_on_your forehead]

ABC is not directly between braces. It's more something like

s/({.*)ABC(.*})/\1DEF\2/g

but as it get's more complicating (more different substitutions), one needs
another solution.

what's wrong with:

s/({.*?)ABC(.*?})/$1DEF$2/g;