syntax incorrect with regex

[sam]

Hi,

What is the correct syntax of declaring a regex syntax in Python 2.3?
I got the following error:

# python2.3 test.py
File "test.py", line 10
macros_parser = re.compile (r""" (\s+)=\"(\s+)\"$ """,re.VERBOS)
^
SyntaxError: invalid syntax

Thanks
sam

 

[Diez B. Roggisch]

Hi,

What is the correct syntax of declaring a regex syntax in Python 2.3?
I got the following error:

# python2.3 test.py
File "test.py", line 10
macros_parser = re.compile (r""" (\s+)=\"(\s+)\"$ """,re.VERBOS)
^
SyntaxError: invalid syntax

No problem here. Is your indentation correct?

 

[Christos TZOTZIOY Georgiou]

macros_parser = re.compile (r""" (\s+)=\"(\s+)\"$ """,re.VERBOS)
^
SyntaxError: invalid syntax

Like Diez already said, your problem is probably mixing of tabs with spaces or
bad indentation in general. The "^" character points at the start of your line,
and errors in regular expressions typically raise sre.error, not SyntaxError.

Is this part of a script or does it come from the command line? If the latter,
don't insert any spaces at the start of your line; if the former, compare
indentation with the line above.

 

[Swaroop C H]

Hi,

What is the correct syntax of declaring a regex syntax in Python 2.3?
I got the following error:

# python2.3 test.py
File "test.py", line 10
macros_parser = re.compile (r""" (\s+)=\"(\s+)\"$ """,re.VERBOS)
^
SyntaxError: invalid syntax

Please check the indentation you have used.
Also, it should be re.VERBOSE (note the ending 'e')

Regards,

 

[Fredrik Lundh]

What is the correct syntax of declaring a regex syntax in Python 2.3?
I got the following error:

# python2.3 test.py
File "test.py", line 10
macros_parser = re.compile (r""" (\s+)=\"(\s+)\"$ """,re.VERBOS)
^
SyntaxError: invalid syntax

compare and contrast:
(no error)
File "<stdin>", line 1
macros_parser = re.compile (r""" (\s+)=\"(\s+)\"$ """,re.VERBOSE)
^
SyntaxError: invalid syntax

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