vector

[Simply_Red]

Hi.


if i have a table of vector:

std::vector<Points>* ArraySol = new std::vector<Points>[nbValues];


to free the memory do i have to do:

for (int i = 0; i<nbValues;i++) ArraySol.clear();
delete[] ArraySol ;


or delete[] ArraySol is enought??

 

[=?ISO-8859-1?Q?Erik_Wikstr=F6m?=]

Hi.


if i have a table of vector:

std::vector<Points>* ArraySol = new std::vector<Points>[nbValues];


to free the memory do i have to do:

for (int i = 0; i<nbValues;i++) ArraySol.clear();
delete[] ArraySol ;


or delete[] ArraySol is enought??

delete[] is enough. Preferably though, you would use a vector or vectors
instead of dynamically allocating an array of vectors.

 

[Simply_Red]

Hi.

if i have a table of vector:

std::vector<Points>* ArraySol = new std::vector<Points>[nbValues];

to free the memory do i have to do:

for (int i = 0; i<nbValues;i++) ArraySol.clear();
delete[] ArraySol ;

or delete[] ArraySol is enought??

delete[] is enough. Preferably though, you would use a vector or vectors
instead of dynamically allocating an array of vectors.

thanks

 

[HuangWei]

It`s engouh. However, it is a good haibit to let a unuseful pointer points a
null.

just like Arraysol = NULL;

 

[Juha Nieminen]

std::vector<Points>* ArraySol = new std::vector<Points>[nbValues];

What's wrong with
std::vector<std::vector<Points> > ArraySol(nbValues); ?