what is wrong with my python code?

[Dongsheng Ruan]

I got feed back saying" list object is not callable". But I can't figure out
what is wrong with my code.

A=[3,5,4,9,6,7]
l=len(A)-1

for i in range(l):
print A(i)

 

[Paul Rubin]

for i in range(l):
print A(i)

Use square brackets, A.

Usually we'd write such a loop like this:

for x in A:
print x

 

[Pierre GM]

I got feed back saying" list object is not callable". But I can't figure
out what is wrong with my code.

for i in range(l):
print A(i)

You're calling A, when you want to access one of its elements: use the
straight brackets [

for i in range(l):
print A

 

[Bruno Desthuilliers]

Dongsheng Ruan a écrit :

I got feed back saying" list object is not callable". But I can't figure out
what is wrong with my code.
>
A=[3,5,4,9,6,7]
l=len(A)-1

for i in range(l):
print A(i)

The error message is quite clear when you remember that () is the call
operator. For the subscribe operator, you want [].

And FWIW, Python for loops are smarter than that:


A = [3,5,4,9,6,7]
for i in A:
print i

 

[John Machin]

I got feed back saying" list object is not callable". But I can't figure out
what is wrong with my code.

A=[3,5,4,9,6,7]
l=len(A)-1

for i in range(l):
print A(i)

What the others said, *plus*:

(1) you are subtracting 1 off the length, so after the change from ()
to [], the last item would not be printed.

(2) have you considered working through a tutorial?

Cheers,
John