XSL Transform

[Ravi]

I am new to XSL. I have a XML document something like

<abc>
xyz
<def> 1 </def>
<def> 2 </def>
<def> 3 </def>
<def> 4 </def>
<def> 5 </def>
</abc>

I am trying to get the value of the abc node which in this case is xyz.
However if I try to get the value using <xsl:value-of select="."/> in a
template matching abc I get

xyz 1 2 3 4 5

which is not what I want. Is there someway to select only the value of
the parent node and then display each child node's value on say a
separate line? I tried using concat and substring-before and though it
works its not a good solution as I do not know how many children abc has
in advance (besides being very laborious). Any suggestions will be
highly appreciated.

TIA.

 

[Dino Morelli]

I am new to XSL. I have a XML document something like

<abc>
xyz
<def> 1 </def>
<def> 2 </def>
<def> 3 </def>
<def> 4 </def>
<def> 5 </def>
</abc>

I am trying to get the value of the abc node which in this case is xyz.
However if I try to get the value using <xsl:value-of select="."/> in a
template matching abc I get

xyz 1 2 3 4 5

which is not what I want. Is there someway to select only the value of
the parent node and then display each child node's value on say a
separate line? I tried using concat and substring-before and though it
works its not a good solution as I do not know how many children abc has
in advance (besides being very laborious). Any suggestions will be
highly appreciated.

To get all of the text values of all of the children of <abc> on
separate lines you can loop through all children:

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xslutput method="text" />

<xsl:template match="/">
<xsl:for-each select="*">
<xsl:value-of select="." />
</xsl:for-each>
</xsl:template>

</xsl:stylesheet>


To get just the single text value of <abc> without the <def> children at
all you can use the text() function:

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xslutput method="text" />

<xsl:template match="/">
<xsl:value-of select="/abc/text()" />
</xsl:template>

</xsl:stylesheet>

 

[Dimitre Novatchev]

I am new to XSL. I have a XML document something like

<abc>
xyz
<def> 1 </def>
<def> 2 </def>
<def> 3 </def>
<def> 4 </def>
<def> 5 </def>
</abc>

I am trying to get the value of the abc node which in this case is xyz.

No, the string value of an element is the concatenation of all of its
descendent text nodes:

From the XPath spec:

"The string-value of an element node is the concatenation of the
string-values of all text node descendants of the element node in document
order."

http://www.w3.org/TR/xpath#element-nodes

However if I try to get the value using <xsl:value-of select="."/> in a
template matching abc I get

xyz 1 2 3 4 5

This is the correct string value of the element (or root node) according to
the XPath spec.

which is not what I want. Is there someway to select only the value of
the parent node and then display each child node's value on say a
separate line?

By "value of the parent node" I guess you mean the value of its first text
node child?

Yes, this transformation produces the results you want:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"<xslutput method="text"/>
<xsl:strip-space elements="*" />

<xsl:template match="text()">
<xsl:value-of select="."/>
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL