yield_all needed in Python

[Isaac To]

Paul> You can work around the need for something like yield_all,
Paul> or explicit loops, by defining an "iflatten" generator,
Paul> which yields every element of its (iterable) argument,
Paul> unless the element is a generator, in which case we recurse
Paul> into it:
Paul> ...

Only if you'd never want to yield a generator.

Regards,
Isaac.