Equation of a line (y=mx+c)

[gbvk]

Hello,

i'm trying to implement "y=mx+c" into code to find the intercept of a
line.


#include <iostream.h>
#include <stdlib.h>
#include <math.h>

void main ()
{
int Ax, Ay, Bx, By;
float Dx, Dy, Dist, Grad;

cout<<"Please enter the 'x' coordinate of the first point: "<<endl;
cin>>Ax;
cout<<"Please enter the 'y' coordinate of the first point: "<<endl;
cin>>Ay;
cout<<"Please enter the 'x' coordinate of the second point: "<<endl;
cin>>Bx;
cout<<"Please enter the 'y' coordinate of the second point: "<<endl;
cin>>By;

Dx=Ax-Bx;
Dy=Ay-By;
Grad= Dy/Dx;

cout<<"Gradient = "<<Grad<<endl;
}

is what i have so far to find "m".

Ex A(2,3) B(6,5)

As I understand the fomula would be;

y-Ay = Grad*(x-Ax)

substituing from A;

y-3=0.5*(x-2)
y-3=0.5x-1
y=0.5x+2

therefore "c" would be: 2

any idea on how i could code this?


G

 

[Victor Bazarov]

i'm trying to implement "y=mx+c" into code to find the intercept of a
line.

[..multiple snips throughout..]
is what i have so far to find "m".

As I understand the fomula would be;

y-Ay = Grad*(x-Ax)

any idea on how i could code this?

y - Ay = Grad * x - Grad * Ax
y = Grad * x - Grad * Ax + Ay

y = Grad * x + (Ay - Grad * Ax)

Does this remind you of something? Please don't ask questions that
don't belong to this newsgroup. Figure your math first, figure your
algorithm second, translate it to C++ to the best of your ability
(even if almost none), then come back asking for help.

V

 

[gbvk]

i'm trying to implement "y=mx+c" into code to find the intercept of a
line.

[..multiple snips throughout..]
is what i have so far to find "m".

As I understand the fomula would be;

y-Ay = Grad*(x-Ax)

any idea on how i could code this?

y - Ay = Grad * x - Grad * Ax
y = Grad * x - Grad * Ax + Ay

y = Grad * x + (Ay - Grad * Ax)

Does this remind you of something? Please don't ask questions that
don't belong to this newsgroup. Figure your math first, figure your
algorithm second, translate it to C++ to the best of your ability
(even if almost none), then come back asking for help.

V

I asked for help on C++ coding.
Sorry Newsgroup commander!

 

[gbvk]

i'm trying to implement "y=mx+c" into code to find the intercept of a
line.

[..multiple snips throughout..]
is what i have so far to find "m".

As I understand the fomula would be;

y-Ay = Grad*(x-Ax)

any idea on how i could code this?

y - Ay = Grad * x - Grad * Ax
y = Grad * x - Grad * Ax + Ay

y = Grad * x + (Ay - Grad * Ax)

Does this remind you of something? Please don't ask questions that
don't belong to this newsgroup. Figure your math first, figure your
algorithm second, translate it to C++ to the best of your ability
(even if almost none), then come back asking for help.

V

strange how I got an answer then isn't it?

 

[Victor Bazarov]

i'm trying to implement "y=mx+c" into code to find the intercept of
a line.

[..multiple snips throughout..]
is what i have so far to find "m".

As I understand the fomula would be;

y-Ay = Grad*(x-Ax)

any idea on how i could code this?

y - Ay = Grad * x - Grad * Ax
y = Grad * x - Grad * Ax + Ay

y = Grad * x + (Ay - Grad * Ax)

Does this remind you of something? Please don't ask questions that
don't belong to this newsgroup. Figure your math first, figure your
algorithm second, translate it to C++ to the best of your ability
(even if almost none), then come back asking for help.

V

strange how I got an answer then isn't it?

You got your answer? Good, there may be a hope for you after
all... Now, did you also learn a lesson? Any? At all? If
you did, whatever it was, I'm glad I've helped. If you didn't,
well, maybe next time.

V

 

[Ron Natalie]

strange how I got an answer then isn't it?

Yep, and nobody pointed out your program is ill-formed and
if you had a compiler that obeyed the standard would have
issued a diagnostic (main must return int).

 

[Juha Nieminen]

I asked for help on C++ coding.
Sorry Newsgroup commander!

No, you asked for a solution to an mathematical problem. The
programming language in which the solution is implemented is irrelevant
in this case.

 

[James Kanze]

On 12 Mar, 16:55, "Victor Bazarov" <[email protected]> wrote:

[...]

strange how I got an answer then isn't it?

I'm not sure what you're point is. The post Victor replied to
wasn't top posted. So why shouldn't he answer it?