"long long" type initialization

[thomas]

Hi,

When I compile the source code with the initialization "long long
p = 1<<60;", an error says that it's not valid.
But I think that "long long" is 64 bits, so "1<<60" certainly
can be hold by "p".
Any suggestions?

Thomas.

 

[Ian Collins]

Hi,

When I compile the source code with the initialization "long long
p = 1<<60;", an error says that it's not valid.
But I think that "long long" is 64 bits, so "1<<60" certainly
can be hold by "p".
Any suggestions?

Does your compiler support long long? It is part of C, but not yet
standardised into C++.

 

[Ian Collins]

Does your compiler support long long? It is part of C, but not yet
standardised into C++.

Even if long long is supported, the compiler is probably objecting to
shifting 1 (which is an int) by more than the number of bits in an int.

try 1LL << 60

 

[thomas]

Even if long long is supported, the compiler is probably objecting to
shifting 1 (which is an int) by more than the number of bits in an int.

try 1LL << 60

Yeah, actually it causes a warning. And it prints "0" for the actual
value when running.
But the "1LL<<60" works well. Thanks.