Need XSL list of XML links

[Donald Firesmith]

How do I use XSL to generate and XHTML list of hyperlinks stored in XML?

My XML contains links of examples of the form:

<examples>
<example>
<link url="aURL">some text</link>
<info>some more text</info>
</example>
<example>
<link url="aURL">some text</link>
<info>some more text</info>
</example>
</examples>

My XSL looks like this:

<ul>
<xsl:for-each select="examples/example">
<li><a href="<xsl:value-of select="@url"/>">
<xsl:value-of select="." disable-output-escaping="yes"/>
<xsl:value-of select="info"/>
</a></li>
</xsl:for-each>
</ul>

I can't seem to get this to work. The url parameter won't fit in the
link. Can anyone show me the proper XSL code for this? Also what
should the XSL code look like if info is optional?

Thanks.

Don

 

[Joris Gillis]

<li><a href="<xsl:value-of select="@url"/>">
Make that <li<a href="{@url}">


regards,

 

[Donald Firesmith]

Make that <li<a href="{@url}">


regards,

Joris
Thanks. That works.
Don

 

[anonymous]

How do I use XSL to generate and XHTML list of hyperlinks stored in XML?

My XML contains links of examples of the form:

<examples>
<example>
<link url="aURL">some text</link>
<info>some more text</info>
</example>
<example>
<link url="aURL">some text</link>
<info>some more text</info>
</example>
</examples>

My XSL looks like this:

<ul>
<xsl:for-each select="examples/example">
<li><a href="<xsl:value-of select="@url"/>">
<xsl:value-of select="." disable-output-escaping="yes"/>
<xsl:value-of select="info"/>
</a></li>
</xsl:for-each>
</ul>

I can't seem to get this to work. The url parameter won't fit in the
link. Can anyone show me the proper XSL code for this? Also what
should the XSL code look like if info is optional?

Thanks.

Don

Look into a construct like this:

<a>
<xsl:attribute name="href">
<xsl:value-of select =....../>
</xsl:attribute>
Link text goes here
</a>

Where your @url stuff goes in the value-of section of the attribute.