question of operator '->' precedence

[Fei Liu]

On Koenig and Moo's 'Accelerated C++' p32, there is a table of operator
precedence, the first group (highest precedence) has x.y, x[y], x++,
x--. I don't see '->' here nor in the table. I believe 'x->y' has the
same precedence as x.y and x[y]. Is my guess correct?

 

[Jakob Bieling]

On Koenig and Moo's 'Accelerated C++' p32, there is a table of
operator precedence, the first group (highest precedence) has x.y,
x[y], x++, x--. I don't see '->' here nor in the table. I believe
'x->y' has the same precedence as x.y and x[y]. Is my guess correct?

Yes, I would say so too.

hth

 

[Daniel T.]

On Koenig and Moo's 'Accelerated C++' p32, there is a table of operator
precedence, the first group (highest precedence) has x.y, x[y], x++,
x--. I don't see '->' here nor in the table. I believe 'x->y' has the
same precedence as x.y and x[y]. Is my guess correct?

<http://www.cppreference.com/operator_precedence.html>

 

[Fei Liu]

On Koenig and Moo's 'Accelerated C++' p32, there is a table of operator
precedence, the first group (highest precedence) has x.y, x[y], x++,
x--. I don't see '->' here nor in the table. I believe 'x->y' has the
same precedence as x.y and x[y]. Is my guess correct?

<http://www.cppreference.com/operator_precedence.html>

awesome, exactly what I need! Thanks, Daniel.