scanf

[sulekhasweety]

scanf(" \"%[^\"]\"",s); means

The scanf will expect a string enclosed within double quotes for
correctly reading the input. Within the double quotes it will accept
any input other than ". It will stop reading at the second "
character.

is this explanation correct..???

 

[sulekhasweety]

scanf(" \"%[^\"]\"",s); means

The scanf will expect a string enclosed within double quotes for
correctly reading the input. Within the double quotes it will accept
any input other than ". It will stop reading at the second "
character.

is this explanation correct..???

Almost. In addition to what you've described, the
scanf() will also read and discard white space (if any)
prior to the first quote mark.

STRONG recommendation: Use something like "%100["
instead of just "%[", to avoid re-inventing the hazards
of gets().

suppose if I change scanf(" \"%[^\"]\"",s); to

scanf("\"%[^\"]\"",s);

the scanf() won't read and discard white space (if any)
prior to the first quote mark. isn't it ?

 

[Robert Gamble]

scanf(" \"%[^\"]\"",s); means

The scanf will expect a string enclosed within double quotes for
correctly reading the input. Within the double quotes it will accept
any input other than ". It will stop reading at the second "
character.

is this explanation correct..???

In addition to Eric's comments, it is worth noting that the "%["
conversion specifier matches *one or more* characters so it will fail
if there are no characters between the quotes, i.e. "".