Using open() inside a subroutine

[imphasing]

Whenever I try to open a file inside a subroutine, like so:

def open():
filePath=askopenfilename()

fileOpen = open(filePath, "r")
fileContent = fileOpen.read()
fileOpen.close()

it tells me that "open() takes no arguments (2 given)"
Why is that? and how can I get around that so I can open a file in a
subroutine?

Thanks,
Alex

 

[Grant Edwards]

Whenever I try to open a file inside a subroutine, like so:

def open():
filePath=askopenfilename()

fileOpen = open(filePath, "r")
fileContent = fileOpen.read()
fileOpen.close()

it tells me that "open() takes no arguments (2 given)"
Why is that?

Because you defined open() as taking no arguments. You're
calling your own open() function, not the builtin one.

and how can I get around that so I can open a file in a
subroutine?

Don't call your function open().

 

[imphasing]

DUH. Thanks.
can't beleive I missed that one...

Alex