what is the error in this program

[Manish Kutaula]

class Customer
@@no_of_customers=0

def initialize(id, name, addr)
@id=id
@name=name
@addr=addr
end

def display_details()
puts "Customer ID #@id"
puts "Customer Name #@name"
puts "Customer Address #@addr"
@@no_of_customers+=1
end

def total_customers
puts "total no. of customers are #@@no_of_customers"
end
end

while($_!="n")
index=0;
print "Enter user id "
id=gets
chomp
print "Enter user name "
name=gets
chomp
print "Enter user address "
addr=gets
chomp
cust=Array.new
cust[index]=Customer.new(id,name,addr)
index+=1
print "do you want to enter more data y/n "
gets
chomp
end

0.upto(index-1) do |c|
puts cust[c].display_details()
end


Whenever i run this program and provide the input the display_details
function show the details of only the last customer.

 

[Sebastian Hungerecker]

while($_!=3D"n")
=C2=A0 index=3D0;
=C2=A0 [...]
=C2=A0index+=3D1
=C2=A0[...]
=C2=A0end

You set index to 0 at every iteration of the loop.

HTH,
Sebastian
=2D-=20
NP: Die Apokalyptischen Reiter - Die Sonne Scheint
Jabber: (e-mail address removed)
ICQ: 205544826

 

[Rick DeNatale]

[Note: parts of this message were removed to make it a legal post.]

On Sat, Jun 14, 2008 at 2:53 PM, Sebastian Hungerecker <

You set index to 0 at every iteration of the loop.

Yes, but beyond that here's a critique of this code in the way of a
refactoring:

class Customer
@@no_of_customers=0 # I personally wouldn't use a class variable here,
but I'll let it go.

def initialize(id, name, addr)
@id=id
@name=name
@addr=addr
# If we are really counting customers we should do it
# when they each customer is created
# not when they are displayed since
# a customer just might get displayed more than once
# or not at all.
@@no_of_customers+=1
end

def display_details()
puts "Customer ID #@id"
puts "Customer Name #@name"
puts "Customer Address #@addr"
end

# I'd make this a class method since the number of customers
# is a property of the class rather than each instance.
def self.total_customers
puts "total no. of customers are #@@no_of_customers"
end
end

# This was just too C/Fortran like, let's treat the array like
# an object, not just a static array!
#
# Since we're collecting the customers here,
# we need to instantiate the array once, not everytime
# through the loop, and let's use a clearer name:

customers = []

# Let's lose the magic variable $_! and make this a
# bit more understandable

more = "y"
# note also that this was $_! = "n" which is an assignment
# NOT a comparison

until(more == "n")
print "Enter user id "
# We need to send chomp to the string we got, not self!
id=gets chomp
print "Enter user name "
name=gets chomp
print "Enter user address "
addr=gets chomp
# Let the array keep track of how many elements it has
customers << Customer.new(id,name,addr)
print "do you want to enter more data y/n "
more = gets chomp
end

# And using each is much less bug prone than a C/Basic/Fortran-like loop:
customers.each do |customer|
puts customer.display_details()
end

I note that this code doesn't actually use the total_customers method, with
the change I made this would be done with

puts Customer.total_customers

However if the real requirement is to get the number of Customers we
processed in the loop, then we can
do away with the counter and the class method and just use

puts customers.length