Windows subprocess.call problem

[Tom Borkin]

Hi;
I have this code:

#!/Python27/python
import os, subprocess, sys
lyrics_path = "/Users/Tom/Documents/lyrics"
os.chdir(lyrics_path)

songs = ['livin-la-vida-loca', 'whos-that-lady']
for song in songs:
subprocess.call(['notepad.exe', '%s.txt' % song])
my_songs_path = "aa english lyrics"
os.chdir(my_songs_path)
for song in my_songs:
subprocess.call(['notepad.exe', '%s.txt' % song])
print song

It opens the first song and hangs on subsequent songs. It doesn't open the
next song or execute the print until I have closed the first one. I want it
to open all in the list, one after another, so I have all those songs
available. Please advise.
TIA,
Tom

 

[Nobody]

It opens the first song and hangs on subsequent songs. It doesn't open the
next song or execute the print until I have closed the first one. I want it
to open all in the list, one after another, so I have all those songs
available. Please advise.

If you want to be able to keep track of the child process (e.g. to
determine when it has finished), use subprocess.Popen(). If you just want
to "fire and forget", use the "start" shell command, e.g.:

subprocess.call(['start', 'notepad.exe', '%s.txt' % song], shell=True)