xslt: multiple node match for one template: how?

[Tjerk Wolterink]

I've made the following template:

<xsl:template match="form:string or form:e-mail or form:url or formassword">
[cut]
</xsl:template>

But the match attribute has an invalid xpath pattern, so i tried this:

<xsl:template match=".[node()=form:string or node()=form:e-mail or node()=form:url or node()=formassword]">
[cut]
</xsl:template>

But that too is not valid!

How should i solve this?

 

[Joris Gillis]

I've made the following template:

<xsl:template match="form:string or form:e-mail or form:url or formassword">
[cut]
</xsl:template>

Hi,

I think that should be:

<xsl:template match="form:string | form:e-mail | form:url | formassword">
[cut]
</xsl:template>


regards,

 

[Martin Honnen]

I've made the following template:

<xsl:template match="form:string or form:e-mail or form:url or
formassword">
[cut]
</xsl:template>

But the match attribute has an invalid xpath pattern, so i tried this:

<xsl:template match=".[node()=form:string or node()=form:e-mail or
node()=form:url or node()=formassword]">
[cut]
</xsl:template>

But that too is not valid!

How should i solve this?

Are you looking for
<xsl:template match="form:string | form:e-mail | form:url |
formassword">
maybe?

 

[Tjerk Wolterink]

I've made the following template:

<xsl:template match="form:string or form:e-mail or form:url or
formassword">
[cut]
</xsl:template>

But the match attribute has an invalid xpath pattern, so i tried this:

<xsl:template match=".[node()=form:string or node()=form:e-mail or
node()=form:url or node()=formassword]">
[cut]
</xsl:template>

But that too is not valid!

How should i solve this?

Are you looking for
<xsl:template match="form:string | form:e-mail | form:url |
formassword">
maybe?

Ok that solved my problem,

but it raises a new question:

In xpath or is the or operator, why use | in xslt??

I think it has something todo with that you do not want a boolean return value from the expression in the match,
you want a node to be returned, am i right?

 

[Tjerk Wolterink]

Ok now i have the following problem:

i've:

<xsl:template match="form:string | form:e-mail | form:url | formassword">
<xsl:if test="current()=formassword">
[cut]
</xsl:if>
</xsl:template>

But the test in the if tag does not work, how should i check wether the current() is a formassword??

name(.)='password' does not help
current()=formassword does not help

please help

 

[Joris Gillis]

In xpath or is the or operator, why use | in xslt??

I think it has something todo with that you do not want a boolean return value from the expression in the match,
you want a node to be returned, am i right?

you're right

the '|' is the union operator for node-sets, while 'or' and 'and' does boolean logic (they return not node-set but a boolean value)

 

[Joris Gillis]

<xsl:if test="current()=formassword">
[cut]
</xsl:if>
</xsl:template>

But the test in the if tag does not work, how should i check wether the current() is a formassword??

Normally, you test something like that with 'self::node'.
But I'm not sure how to handle the namespace. one guess: 'self::formassword'

 

[David Carlisle]

use | not or
or is an Xpath boolean operator an XSLT patterns have to match nodes not
boolean values.

David